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Kipish [7]
3 years ago
9

Can anybody help me out with this it’s due tomorrow please?

Mathematics
1 answer:
pogonyaev3 years ago
3 0
For the first question you just need to add up all the sides. so first add all the x numbers and then add all the plain numbers.
a perimeter is the total length around the shape.
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*square root symbol* y^3 multiplied by *square root symbol* y^3
san4es73 [151]
The product of two radicals is equal to the radicand. The square root deletes itself.

So the result is y^3
8 0
3 years ago
Read 2 more answers
IMG_9606.JPG Help on all of it plzz
erastova [34]
What's ur question bc when i search <span>IMG_9606.JPG it says that nothing exists.</span>
8 0
3 years ago
Pls help me this is due tomorrow
Anna [14]

Step-by-step explanation:

Claim: There's 14 Goats and 9 Chickens!!

Data:

Working with the Provided Information.

Let the Number of goats be x

let the Number of Chickens be y

x + y = 23..... (i)

Since the goat Possesses Two Pair of Legs... Which is a Total of 4 Legs... We say Let its Contribution be 4x.

The Chicken has Only a Pair Of Legs...Which is a total of 2 legs.... We say let its contribution be 2y

4x + 2y = 74 .....(ii)

BRINGING BOTH EQUATIONS TOGETHER.

x + y = 23

4x + 2y = 74

From Eqn i

x= 23 - y

Substitute into eqn ii

4(23 - y ) + 2y = 74

92 - 4y + 2y = 74

92 - 2y = 74

2y = 92 - 74

2y = 18

y= 9.

Substitute y into any of the eqns to get x

x + y = 23

x + 9=23

x = 23 - 9

x = 14

This simply proves that there are 14 Goats and 9 Chickens!!!.

HAVE A GREAT DAY!

7 0
3 years ago
How do i find the measure of these? i’m lost in math
Rina8888 [55]

Answer: Answers and work are all in the picture that I attached. Hope this helps

7 0
2 years ago
Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312k
Zina [86]

Answer:

Speed of car B is 33 km/h and speed of car A is 45\,\,km/h

Step-by-step explanation:

Let speed of car B be x km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = (12+x) km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = 4(12+x) km = (48+4x) km

Distance travelled by car B in 4 hours = 4x km

Also, cars A and B are 312km apart after 4 hours.

48+4x+4x=312\\48+8x=312\\8x=264\\\\x=\frac{264}{8}\\\\x=33\,\,km/h

Speed of car B is 33 km/h and speed of car A is 12+x=12+33=45\,\,km/h

5 0
2 years ago
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