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Oksi-84 [34.3K]
3 years ago
10

4) If rectangle WXYZ has slid three units to the right what will be the coordinates of point W?

Mathematics
2 answers:
NikAS [45]3 years ago
8 0
D. (6, 2)
have a nice day!
uranmaximum [27]3 years ago
4 0
D

Its now in (3,2) if goes right 3 points then x becomes 6 so (6,2)
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a) \bar X = 52

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Step-by-step explanation:

For this case we have the following dataset:

55 56 44 43 44 56 60 62 57 45 36 38 50 69 65

A total of 15 observations

Part a

We calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^{15} X_i}{15}

And for this case we got \bar X = 52

For the median we ust need to order the data on increasing way like this:

36, 38,43,44,44,45,50,55,56,56,57,60,62,65,69

Since the number of observations is an odd number the median would be on the 8 position from the dataset ordered on this case:

Median = 55

Part b

In order to calculate the Q1 we need to select the following data:

36, 38,43,44,44,45,50,55

And the Q1 would be the average between the 4 and 5 positions like this:

Q_1= \frac{44+44}{2}=44

And for the Q3 we select these values:

55,56,56,57,60,62,65,69

And the Q3 would be the average between the 4 and 5 positions like this:

Q_3= \frac{57+60}{2}=58.5

Part c

The Range is defined as:

Range = Max -Min = 69-36=33

Part d

In order to calculate the sample variance we can use the following formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

And if we replace we got:

s^2 =100.1429

And the deviation is just the square root of the variance:

s= \sqrt{100.143}=10.0071

Part e

For this case we need to find the lower and upper limits for the boxplot given by:

Lower = Q_1 -1.5 IQR = 44-1.5(58.5-44) = 22.25

Upper = Q_1 +1.5 IQR = 44+1.5(58.5-44) = 65.75

A possible outlier would be the value of 69 since its above the upper limti for the boxplot.

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