1.1, 1.3, 1.5. Your just adding .2 to the number each time
Thw answer is -51
Found through long division
hello
the question here is
![3\sqrt[]{7}(14-4\sqrt[]{56})](https://tex.z-dn.net/?f=3%5Csqrt%5B%5D%7B7%7D%2814-4%5Csqrt%5B%5D%7B56%7D%29)
step 1
multiply through the bracket by the coeffiecient
![\begin{gathered} 3\sqrt[]{7}(14-4\sqrt[]{56}) \\ (3\sqrt[]{7}\times14)-(3\sqrt[]{7}\times4\sqrt[]{56}) \\ (14\times3\sqrt[]{7})-3\sqrt[]{7}\times4\sqrt[]{4\times14} \\ (42\sqrt[]{7})-3\sqrt[]{7}\times8\sqrt[]{14} \\ (42\sqrt[]{7})-\lbrack(3\times8)\sqrt[]{7\times14} \\ 42\sqrt[]{7}-24\sqrt[]{98} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203%5Csqrt%5B%5D%7B7%7D%2814-4%5Csqrt%5B%5D%7B56%7D%29%20%5C%5C%20%283%5Csqrt%5B%5D%7B7%7D%5Ctimes14%29-%283%5Csqrt%5B%5D%7B7%7D%5Ctimes4%5Csqrt%5B%5D%7B56%7D%29%20%5C%5C%20%2814%5Ctimes3%5Csqrt%5B%5D%7B7%7D%29-3%5Csqrt%5B%5D%7B7%7D%5Ctimes4%5Csqrt%5B%5D%7B4%5Ctimes14%7D%20%5C%5C%20%2842%5Csqrt%5B%5D%7B7%7D%29-3%5Csqrt%5B%5D%7B7%7D%5Ctimes8%5Csqrt%5B%5D%7B14%7D%20%5C%5C%20%2842%5Csqrt%5B%5D%7B7%7D%29-%5Clbrack%283%5Ctimes8%29%5Csqrt%5B%5D%7B7%5Ctimes14%7D%20%5C%5C%2042%5Csqrt%5B%5D%7B7%7D-24%5Csqrt%5B%5D%7B98%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} 42\sqrt[]{7}-24\sqrt[]{49\times2} \\ 42\sqrt[]{7}-24\times7\sqrt[]{2} \\ 42\sqrt[]{7}-168\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2042%5Csqrt%5B%5D%7B7%7D-24%5Csqrt%5B%5D%7B49%5Ctimes2%7D%20%5C%5C%2042%5Csqrt%5B%5D%7B7%7D-24%5Ctimes7%5Csqrt%5B%5D%7B2%7D%20%5C%5C%2042%5Csqrt%5B%5D%7B7%7D-168%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
Answer:
solution below
Step-by-step explanation:
The question says 6 working mother's were selected so <u>n = 6</u><u> </u><u>not</u><u> </u><u>0</u><u>.</u><u>6</u>
We are expected to find
P(X = 0,1,2,3,4,4,6)
1. <u>When x = 0</u>
6C0*(0.34)⁰*(0.66)⁶
= 1 *1* 0.827
= 0.0827
<u>2. When X = 1</u>
6C1*(0.34)¹*(0.66)⁵
= 6 x 0.34 x 0.252
= 0.2555
<u>3. When X = 2</u>
6C2*(0.34)²*(0.66)⁴
= 15 x 0.1156 x 0.1897
= 0.3289
<u>4. When x = 3</u>
6C3*(0.34)³*(0.66)³
20 x 0.039304 x 0.2875
= 0.2599
<u>5. When X = 4</u>
6C4*(0.34)⁴*(0.66)²
= 15 x 0.01336 x 0.4356
= 0.8729
<u>6. When x = 5</u>
6C5*(0.34)⁵*(0.66)¹
= 6 x 0.0045 x 0.66
= 0.01782
<u>7. When x = 6</u>
6C6*(0.34)⁶*(0.66)⁰
1 x 0.0015 x 1
= 0.0015
