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Mashutka [201]
3 years ago
7

The world's narrowest vehicle is about 35 inches wide how wide is this vehicle to the nearest Foot

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0
35 divided by 12, is 2.196 repeating so about 3. 
Montano1993 [528]3 years ago
5 0
I think the answer is three
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Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex
natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

Finding the curl of F.

Given F(x,y,z) = < yz, 4xz, e^{xy} > we have:

curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|

Working with the determinant we get

curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k

Working with the partial derivatives

curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS

where the normal to the circle is just \hat n= \hat k since the normal is perpendicular to it, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS

Only the z-component will not be 0 after that dot product we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3z dS

Since the circle is at z = 3 we can just write

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3(3) dS\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 9\int \int_S dS

Thus the integral represents the area of a circle, the given circle x^2+y^2 = 9 has a radius r = 3, so its area is A = \pi r^2 = 9\pi, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = 9(9\pi)\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 81 \pi

Thus the result of the integral is 81π

5 0
3 years ago
True or false: Metals are usually found in covalent compounds
Furkat [3]

Answer: True

Hope this helps! ^^

6 0
3 years ago
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What is 34 + 35?<br><br><br><br><br> does anyone like anime lol.
jeka57 [31]
There is no carrying so you add 5 and 4 with is 9 and 3 and 3 which 6 so the answer is 69
5 0
3 years ago
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Hey! please help i’ll give brainliest!
Debora [2.8K]

Answer:

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Step-by-step explanation:

Both forces have the same amounts being applied to on the brick, so the forces will cancel each other out and have no effect on the brick, so the brick won't move.

5 0
3 years ago
The table shows values for functions f(x) and g(x) .
lozanna [386]

Answer:

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Step-by-step explanation:

Let's work through this step by step.

x goes from -2 to 2 so we will check each integer in between.

f(-2) and g(-2) is the first one.  The table shows f(-2)=-8 and g(-2)=-2, so f(-2) does not equal g(-2)

Now we just keep doing this for x=-1,0,1, and 2

f(-1) = -1 and g(-1) = -1 so f(-1)=g(-1)

f(0)=0 and g(0)=0 so f(0)=g(0)

f(1)=1 and g(1)=1 so f(1)=g(1)

f(2)=8 and g(2)=2 so f(2) does not equal g(2)

So there were three xs that made f(x) = g(x).  -1, 0 and 1, so those are your answers.  

8 0
3 years ago
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