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4 years ago

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

Mathematics

1 answer:

Makovka662 [10]4 years ago

6 0

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! / (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

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James determined that these two expressions were equivalent expressions using the values of x=4 and x =6 Which statements are tr

almond37 [142]

Solution:

The Expression

P = 7 x + 4

Q = 3 x + 5 + 4 x -1

Adding like terms , i.e term containing variables and term containing constants

Q = 3 x + 4 x + 5 -1 [You must be thinking why i have written this, keep in mind Commutative law of addition which is , a + b = b + a, i.e in this expression , 5 + 4 x = 4 x + 5]

So, Q = 7 x + 4

As you can see both P and Q are identical Expressions.

Now we will check each and every option.

1. When x= 2,

P =Q= 7 × 2 + 4= 14 + 4= 18→→→→(True)

2. As for x=4,6

P = Q = 7 × 4 +4=28 + 4=32

P = Q= 7× 6 +4 = 42 +4=46

As , explained above, We saw that both the expressions P and Q are identical.

So , There are infinite values of x , for which these Expression P and Q are identical.

Statement 2 is not true i.e False.

3. Statement 3 , is false.→→→[Explained above]

4. True →→The expressions have equivalent values for any value of x.

5. False →→→The expressions should have been evaluated with one odd value and one even value.

6. False →→→As ,P =Q Both expressions are identical. [When x=0, the first expression has a value of 4 and the second expression has a value of 5.]

7. True, As, P = Q, so both the expression P and Q have same value for x=8.

6 0

3 years ago

Read 2 more answers

How can you generate x-3y+5 from the expression x+y+4+2y+1

vladimir2022 [97]

Answer: Here is the explanation. also it it +3y not -3y

Step-by-step explanation:

x+y+4+2y+1=x+3y+5 because

2y+y=3y

so now you have x+3y+4+1

4+1=5

now you have: x+3y+5

if you do not understand, What i am trying to say is, you need to add all of the same things.

3 0

4 years ago

Valerie is taking a road trip over spring break. At 4:30 p.m. she looks down at her speedometer and notices that she is going 45

hammer [34]

Answer:

b. 4:35 p.m

Step-by-step explanation:

Her speed in t minutes after 4:30 p.m. is modeled by the following equation:

$v(t) = v(0) + at$

In which v(0) is her speed at 4:30 pm and a is the acceleration.

At 4:30 p.m. she looks down at her speedometer and notices that she is going 45 mph.

This means that $v(0) = 45$

Ten minutes later she looks down at the speedometer again and notices that she is going 55 mph.

This means that $v(10) = 55$

$v(t) = v(0) + at$

$55 = 45 + 10a$

$10a = 10$

$a = 1$

$v(t) = 45 + t$

When was she moving exactly 50 mph?

This is t minutes after 4:30 p.m.

t is found when v(t) = 50. So

$v(t) = 45 + t$

$50 = 45 + t$

$t = 5$

5 minutes after 4:30 p.m. is 4:35 p.m.

So the correct answer is:

b. 4:35 p.m

4 0

4 years ago

Solve the system: 2x+3y=6 and x=-2y+3. I need help

Alex Ar [27]

Answer:

$\large\boxed{x=3,\ y=0\to(3,\ 0)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+3y=6&(1)\\x=-2y+3&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\2(-2y+3)+3y=6\qquad\text{use distributive property}\\\\(2)(-2y)+(2)(3)+3y=6\\\\-4y+6+3y=6\qquad\text{subtract 6 from both sides}\\\\-y=0\to\boxed{y=0}\\\\\text{Put the value of y to (2):}\\\\x=-2(0)+3\\\\x=0+3\\\\\boxed{x=3}$

3 0

3 years ago

Find all integer solutions to 14x + 77y = 69.

Katena32 [7]

Integer solutions doesn't exist.

8 0

3 years ago