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4 years ago

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

Mathematics

1 answer:

Makovka662 [10]4 years ago

6 0

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! / (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

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Brainiest if correct or first<br> 1/2(6x+1/2)

Alexxx [7]

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

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3 years ago

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Harlamova29_29 [7]

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Step-by-step explanation:

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