How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?
1 answer:
Answer:
24,192.
Step-by-step explanation:
The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.
The number of permutations of the other 4 numbers is 9P4
= 9! / (9-4)!
= 3024
Now we multiply by the 8:
3024 * 8
= 24,192.
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Step-by-step explanation:
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