This is C. cos Z = sin (90 - Y)
We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer <span>
considering the case N 2 </span>
isvertex (4,-1)------> is correcty intercept (0,-17)-----> is correctaxis of symmetry x=4-----> is correct
Answer:
A(3) = -6 + (3 - 1) (5)
-6 + (2)(5)
-6 + (10)
4
A(4) = -6 + (4 - 1) (5)
-6 + (3)(5)
-6 + 15
9
A(10) = -6 + (10 - 1) (5)
-6 + (9)(5)
-6 + 45
39
The slope is 3 and y-intercept is 4
y=mx+b