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Sauron [17]
3 years ago
5

A scientist mixes water (containing no salt) with a solution that contains 35% salt. She wants to obtain 245 ounces of a mixture

that is 15% salt. How many ounces of water and how many ounces of the 35% salt solution should she use?
Mathematics
1 answer:
sesenic [268]3 years ago
8 0

Answer:

140 ounces of water and 105 ounces of 35% salt solution.

Explanation:

Let x be the ounces of water that need to be added and y be the ounces of 35% solution that need to to be added.

We know that the total of ounces of water and of 35% solution must be 245 ounces:

x+y=245

35% of  x is the salt, and since no salt is added with addition of y  liters of water, this must be equal to the amount of salt in the final 15% solution:

0.35x=0.15*245

we solve for  x and get:

x=105

We put this value into x+y=245 and solve for y to get:

y=140

Thus we have 140 ounces of water and 105 ounces of 35% solution.

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18. 84 ft² or 18.85 ft² when rounded to the nearest tenth

Step-by-step explanation:

2πrh+2πr²

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2 × 3.14 × 1² = 6.28

12.56 + 6.28 = 18.84

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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
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1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
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In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
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In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
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  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
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  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

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