A store has apples on sale for $3.00 for 2 pounds. How many pounds of apples can you buy for $9? If an apple is approximately 5
2 answers:
Since 2 pounds is $3 and you have $9, you would do:
, x= # of pounds of apples
You do cross multiplication to get:
x=6
1 lb= 16 oz
So
to get the number of ounces you can buy for $9.
Then divide 96 by 5, so that is ABOUT 19 APPLES.
You do cross multiplication to get:
x=6
1 lb= 16 oz
So
Then divide 96 by 5, so that is ABOUT 19 APPLES.
we know that
A store has apples on sale for $ for
pounds
Part a) How many pounds of apples can you buy for $?
by using proportion
therefore
the answer Part a) is
Part b) If an apple is approximately ounces, how many apples can you buy for $
?
we know that
step 1
convert ounces to pounds
by using proportion
therefore
the answer part b) is
about
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Answer:
α ≥ 48.2°
Step-by-step explanation:
The complete question is given as follows:
" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to the skier make with the vertical?"
- The figure is also attached.
Solution:
- The skier has a mass (m) and the snowball’s radius (r).
- Choose the center of the snowball to be the zero of gravitational potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and departs from the snowball.
- If we ignore snow-ski friction along with air resistance, then the one work producing force in this problem, gravity, is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical energy at the top of the snowball.
- Hence, From conservation of energy we have:
KE (α) + PE(α) = KE(α = 0) + PE(α = 0)
0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r
0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r
m*v(α)^2 / r = 2*m*g( 1 - cos(α) )
- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity can hold her to that path, i.e. as long as:
m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )
- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal force—or else the skier will sink into the snowball.
- The expression for α_lift becomes:
3*cos(α) ≥ 2
α ≥ arc cos ( 2/3) ≥ 48.2°
The quotient of the provided division in which binomial is divided by a quadratic equation is x+2.
<h3>What is the quotient?</h3>Quotient is the resultant number which is obtained by dividing a number with another. Let a number <em>a</em> is divided by number b. Then the quotient of these two number will be,
Here, (a, b) are the real numbers.
The given division expression is,
Let the quotient of this division problem is f(x). Thus,
Factor the numerator expression as,
Thus, the quotient of the provided division in which binomial is divided by a quadratic equation is x+2.
Learn more about the quotient here;