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telo118 [61]
3 years ago
9

20-%204%29%20" id="TexFormula1" title="( {x}^{3} - 8 {x}^{2} + 19x - 9) \div (x - 4) " alt="( {x}^{3} - 8 {x}^{2} + 19x - 9) \div (x - 4) " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anna [14]3 years ago
6 0

(x^3-8x^2+19x-9)\div(x-4)=x^2-4x+3\\\underline{-x^3+4x^2}\\=-4x^2+19x\\\underline{\ \ \ \ \ 4x^2-16x}\\.\ \ \ =3x-9\\\underline{\ \ \ \ \ -3x+12}\\.\ \ \ \ \ =\ 3

x^3-8x^2+19x-9=(x^2-4x+3)(x-4)+3



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The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
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Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

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We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

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We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

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The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
Need help please :)
swat32

Answer:

acute

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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