<img src="https://tex.z-dn.net/?f=%28%20%7Bx%7D%5E%7B3%7D%20-%208%20%7Bx%7D%5E%7B2%7D%20%20%2B%2019x%20-%209%29%20%5Cdiv%20%28x%

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3 years ago

20-%204%29%20" id="TexFormula1" title="( {x}^{3} - 8 {x}^{2} + 19x - 9) \div (x - 4) " alt="( {x}^{3} - 8 {x}^{2} + 19x - 9) \div (x - 4) " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Anna [14]3 years ago

6 0

$(x^3-8x^2+19x-9)\div(x-4)=x^2-4x+3\\\underline{-x^3+4x^2}\\=-4x^2+19x\\\underline{\ \ \ \ \ 4x^2-16x}\\.\ \ \ =3x-9\\\underline{\ \ \ \ \ -3x+12}\\.\ \ \ \ \ =\ 3$

$x^3-8x^2+19x-9=(x^2-4x+3)(x-4)+3$

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