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ss7ja [257]
3 years ago
9

What decimal is equivalent to 4/3?

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
7 0

Answer:

1.33333........    =     1(1/3)

Step-by-step explanation:

4/3 is an improper fraction

The mixded number is 1  1/3

 OR

1.33333  = 1 and 3/9    =  1 and 1/3

Finger [1]3 years ago
6 0

Answer:

1.333.......

Step-by-step explanation:

Mixed form=1 1/3

1/3 in decimal form is 0.333....

Decimal form=1+0.333......

=1.33333.....

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6z^2+7x^3+8x^5+9 the degree of the polynomial
hoa [83]

Answer: 5 is the degree

Step-by-step explanation:

6 0
3 years ago
Find the value of x in each triangle
ankoles [38]
I would have to say that the angle is 61 degrees but this may not be correct so you know <span />
8 0
3 years ago
Read 2 more answers
Madhu's age is 3 times Sanku's age and difference between their ages is 14. Then find their ages?
marysya [2.9K]
Let’s take Sanku as x.
if Madhu is 3 times his age, then he is 3x.
the difference in their age is 14, so
3x - x = 14
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4 0
4 years ago
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In △ABC, point D∈ AC with AD:DC=4:3, point E∈ BC so that BE:EC=1:5. If ACDE=5 in2, find ABDC, AABD, and AABC.
Kaylis [27]

Answer:

ar ΔBDC=6 in^2

ar ΔABD=8 in^2

ar ΔABC=14 in^2

Explanation:

Please take a look of attach figure.

We are given area of triangle ar ΔCDE=5 in^2

ar ΔCDE=\frac{1}{2}\times DN\times EC------------(1)

ar ΔBDE=\frac{1}{2}\times DN\times BE------------(2)

Divide eq(2) by eq(1) and we get,

\frac{ar\ ΔBDE}{ar\ ΔCDE}=\frac{BE}{EC}

\frac{ar\ ΔBDE}{5}=\frac{1}{5}

So, ar ΔBDE=1 in^2

ar ΔBDC=ar ΔBDE+ ar ΔCDE

ar ΔBDC=1+5 = 6 in^2

Similarly,

\frac{ar\ ΔABD}{ar\ ΔBDC}=\frac{AD}{DC}

\frac{ar\ ΔABD}{6}=\frac{4}{3}

ar ΔABD=8 in^2

ar ΔABC=ar ΔABD + ar ΔBDC

ar ΔABC=8+6 = 14 in^2

6 0
3 years ago
What is the value of v? Please provide an explanation, thanks!
san4es73 [151]

Answer:

13

Step-by-step explanation:

(180-(11v+15)+9v-8+6v-9=180

4v+148=180

4v=52

v=52/4

=13°

7 0
3 years ago
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