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blagie [28]
3 years ago
5

In the 1996 presidential election, Bill Clinton and Bob Dole together received 538 electoral votes. Clinton received 220 more vo

tes than Dole. How many votes did each candidate get?
Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:


Step-by-step explanation:

Bill + 220

Total is 538 so subtract 220 which gives you 318.

318/2 = 159

159+220 for Bill = 379

Bob has 159

Add 159 + 220 for Bill and 159 for bob = 538

So Bill has 379

and Bob has 159

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In na hour , a jogger burns about 4 calories pero pound of body weight. How Manu calories will a jogger who weighs 151 pounds in
Alex777 [14]

This is a rate*unit problem.


So, 4 calories per pound x 151 pounds

4\times151=604

He will burn 604 calories in one hour

6 0
3 years ago
(-6time + 3) + (5time -4)
Fynjy0 [20]

Answer:

-2

Step-by-step explanation:

18+-20

-2

3 0
3 years ago
Find the measure of angle A​
Sladkaya [172]

Answer:

40°

X=11

I can't give you a very good explanation because I'm

only a freshman lol, I only studied so far in this stuff so I think ill stick to questions like this that give me side lengths and require an angle.

Anyways, hope this helped!

4 0
3 years ago
Which of the following expressions are equivalent to -0.5(1.7+1.7)−0.5(1.7+1.7)minus, 0, point, 5, left parenthesis, 1, point, 7
Allisa [31]

The expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)

and 2(-0.5(1.7))

<h3>Distributive law of expansion</h3>

Given the expression below;

-0.5 (1.7 + 1.7)

According to the distributive law;

A(B+C) = AB + AC

Expand

-0.5(1.7) + (-0.5)(1.7)

-0.5(1.7) - 0.5(1.7)

2(-0.5(1.7))

Hence the expressions equivalent to -0.5(1.7+1.7) are -0.5(1.7) - 0.5(1.7)

and 2(-0.5(1.7))

Learn more on distributive law here: brainly.com/question/25224410

#SPJ1

7 0
2 years ago
Helpppppppppppppppppp!
julia-pushkina [17]
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.

If the domain has already been restricted to x \geq -11, we can work backwards to add 11 to both sides. We see that x+11 must be under the radicand, so the answer is A.
7 0
3 years ago
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