Answer:
-23
Step-by-step explanation:
Because it is.
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Answer:
12,13 and 14
Step-by-step explanation:
Let the three consecutive integers be n, n+1 and n+2
ATQ,
The sum of twice the second integer and 4 times the third integer is two less than seven times the first integer.
[2(n+1)+4(n+2)] = 7n-2
or
2n+2+4n+8=7n-2
Taking like terms together,
6n-7n = -2-8-2
n = 12
So,
First integer = 12
Second integer = 12+1 = 13
Third integer = 12+2 = 14
Hence, three consecutive integers are 12,13 and 14.
−5x 3 −x−9+2x 2
(I think) my apologies if it’s incorrect