Based on the information given the percentage of the brown geese that are heterozygous is 48%.
Random sample = 250
Brown color = 210
Gray color = 250 - 210 = 40
First step is to calculate the proportion of a alleles in the population
Proportion (a alleles)=√40/250
Proportion (a alleles)= √0.16
Proportion (a alleles)= 0.4
Second step is to calculate the proportion of A alleles in the population
p(A) = 1 - 0.4
p(A)= 0.6
Third step is to calculate brown heterozygous percentage using this formula
Brown heterozygous percentage=2pq(Aa)
Let plug in the formula
Brown heterozygous percentage= 2 x 0.6 x 0.4
Brown heterozygous percentage= 0.48 ×100
Brown heterozygous percentage= 48%
Inconclusion the percentage of the brown geese that are heterozygous is 48%.
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Step-by-step explanation:
7+5(x) ( between here write the greater than or equal to sign) -9
Answer:
see explanation
Step-by-step explanation:
Choose any value for x, substitute into the equation and solve for y, that is
x = - 1
2(- 1) + y = 8
- 2 + y = 8 ( add 2 to both sides )
y = 10
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x = 0
2(0) + y = 8
0 + y = 8
y = 8
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x = 1
2(1) + y = 8
2 + y = 8 ( subtract 2 from both sides )
y = 6
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x = 3
2(3) + y = 8
6 + y = 8 ( subtract 6 from both sides )
y = 2
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4 possible solutions are (- 1, 10 ), (0, 8 ), (1, 6 ) and (3, 2 )
Answer: So you want to work with PEMDAS which you probably remember from Elementary school. Start in the parentheses. What you want to do is multiply your squares, after simplifying. So if you have -a^2 that would be -a multiplied by -a. Then you have -b^3 so that would be -b multiplied by -b multiplied by -b so now your equation will look like this -7 x -a x -a x -b x -b x -b. Negative times a negative is a positive... so -a x -a = a and -b x -b x -b = a negative -b. So the equation simplified is -7 x a x -b. Try and figure it out from there. I apologize if I'm wrong. I struggle with math also. I'm also not sure what kind of algebra this is. Good luck.
Step-by-step explanation: