Another algebra question :/
2 answers:
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9514 1404 393
Explanation:
<u>Part A</u>.
1. You have provided an estimate of 600 minutes per month.
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2. The cheapest plan is likely to be Plan 6 (Public Mobile), as it has no per-minute charge.
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<u>Part B</u>.
1. Table 2.
See the first attachment for Table 2. For the chosen plan, there is no per-minute charge, so the monthly charge is the same for all numbers of minutes.
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2. Rate of Change and Slope (m)
a) Adding a minute adds $0 to the cost
b) The rate of change (m) is 0/1 = 0 (dollars per minute)
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3. Initial value (b)
a) The plan costs $24.00 when no minutes are used.
b) The initial value (b) is 24.
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4. Equation of the line
a) Filling the found values of m and b into the equation of the line, we have ...
y = mx + b
y = 0x + 24
y = 24 . . . . . . simplified
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<u>Part C</u>.
Table 3 can be found in the second attachment.
The b in each case is the value from the <em>Monthly Cost</em> column of Table 1.
The m in each case is the value from the <em>Cost per minute</em> column of Table 1.
The equation is found by copying the values of m and b into y = mx + b.
The number in the last column is found by multiplying the minutes (x) by m, then adding b. <em>For example</em>, your cost for Plan 5 (BELL) is ...
y = 0.10x + 10
y = (0.10)(600) +10 = 60 +10 = 70
