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2 years ago

What is the quotient? startfraction 3 y 2 over 3 y endfraction divided by startfraction 6 y squared 4 y over 3 y 2 endfraction

Mathematics

1 answer:

Ludmilka [50]2 years ago

7 0

The quotient of the expression $\frac{3y+2}{3y} divided \frac{6y^{2} + 4y}{3y + 2}$ is 3y + 2 / 6y

<h3>How to find quotient of an expression?</h3>

The quotient of the expression can be found as follows:

3y + 2 / 3y ÷ 6y² + 4y / 3y + 2

Therefore,

3y + 2 / 3y × 3y + 2 / 6y² + 4y

Hence,

3y + 2 / 3y × 3y + 2 / 2y(3y + 2)

Therefore,

1 / 3y × 3y + 2 / 2

Hence,

3y + 2 / 2(3y)

3y + 2 / 6y

learn more on quotient here:brainly.com/question/16590279

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Answer:

p = 25,20 cm

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Step-by-step explanation:

Let call p and h dimensions of a poster, ( length , and height respectively) and x and y dimensions of the printed area of the poster then

p = x + 8 and h = y + 12

Printed area = A(p) = 384 cm² and A(p) = x*y ⇒ y = A(p)/x

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Poster area = A(t) = ( x + 8 ) * ( y + 12 ) ⇒ A(t) = ( x + 8 ) * [( 384/x ) + 12 ]

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A(t) = [480x + 12x² + 3072 ] / x

A´(t) = [(480 + 24x )* x - (480x + 12x² + 3072]/x²

A´(t) = 0 [(480 + 24x )* x - 480x - 12x² - 3072] =0

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x = 17,20 cm and y = 384/17,20 y = 22,32 cm

Notice if you substitu the value of x = 17,20 in A(t) ; A(t) >0 so we have a minimun at that point

Then dimensions of the poster

p = 17,20 + 8 = 25,20 cm

h = 22.32 + 12 =34,32 cm

A(min) = 25,20 *34.32

A(min) = 864,86 cm²

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