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3 years ago

The area of a square painting is 1,600 cm2. What is the side length of the painting?

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

$\sqrt{1600} 
$

= 40

sides are 40 long each

Aleksandr-060686 [28]3 years ago

7 0

40
there are fourty bro

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TU has endpoints at T(5, 11) and U(-4, -1). How long is TU?<br> Please help me

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3 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

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3 years ago

A cyclist is stationary when a second cyclist passes travelling at a constant speed of 8 m s−1. The first cyclist then accelerat

DerKrebs [107]

Answer:

im not too sure about that sorry!

Step-by-step explanation:

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2 years ago

Fill in the blank with the recursive function. Be sure to include the starting point.

erik [133]

Answer:

The recursive function that represents the number of books Ashley has at any time is

$a_n=a_{n-1}-n$

starting at

$a_1=100$

Step-by-step explanation:

Ashley has 100 books that she wants to give away at the rate of n books per week.

So,

$a_1=100\\ \\a_2=100-n=a_1-n\\ \\a_3=a_2-n\\ \\...\\ \\a_n=a_{n-1}-n$

Thus, the recursive function that represents the number of books Ashley has at any time is

$a_n=a_{n-1}-n$

starting at

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3 years ago

Math To Do, i-Ready

marysya [2.9K]

Answer:

The price before tip ,Mrs. Henry's move is 351.9 $

Step-by-step explanation:

Given:

Total bills of 414 $ in which 15 % is tip

To Find:

What is the price before tip, Mrs. Henry's move

Solution:

Total bill amount is 414$

And 15 % is tip bill and 85 % is bill before tip

So,

85 % of total bill can give price before tip

calculate 15 % and subtract from total bill.

So 85 % of 414=0.85 *414

=351.9 $

15 % 414=0.15 *414

=62.1 $

Price before Tip is =414$ -62.1 $

=351.9$

So BY Both ways we can get same answer i.e. 351.9 $

8 0

3 years ago

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