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9966 [12]
3 years ago
13

Quadrilateral ABCD ​ is inscribed in this circle.

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

The measure of angle A is 65°

Explanation:

Given that ABCD is a quadrilateral inscribed in a circle.

The measure of angle A is \angle A=(2x+1)^{\circ}

The measure of angle B is \angle B=148^{\circ}

The measure of angle D is \angle D=x^{\circ}

We need to determine the measure of angle A.

Since, we know that the angles B and D are opposite angles and the opposite angles of a quadrilateral add up to 180°

Thus, we have,

\angle B+\angle D=180^{\circ}

Substituting the values, we have,

148^{\circ}+x=180^{\circ}

          x=32^{\circ}

Thus, the value of x is 32°

Substituting the value of x in the measure of angle A, we get,

\angle A=(2x+1)^{\circ}

\angle A=(2(32)+1)^{\circ}

\angle A=(64+1)^{\circ}

\angle A=65^{\circ}

Thus, the measure of angle A is 65°

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