What is the location of A’ and did the figure get larger or smaller?

Mathematics

1 answer:

storchak [24]1 year ago

3 0

Scale Factor is defined as the ratio of the size of the new image to the size of the old image. The center of dilation is a fixed point in the plane.

If the scale factor is more than 1, then the image stretches. If the scale factor is between 0 and 1, then the image shrinks. If the scale factor is 1, then the original image and the image produced are congruent.

To dilate a figure by a scale factor, all the coordinates are multiplied by the scale factor.

The coordinates of point A are (8, 6). A dilation by a scale factor of 0.5 means that the figure will be reduced. The new coordinates will be:A

$\begin{gathered} A^{\prime}=(0.5\times8,0.5\times6) \\ A^{\prime}=(4,3) \end{gathered}$

Therefore, the FIRST OPTION is correct.

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Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes

valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

$x =\frac{16}{2}$

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment $\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}$