Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.
<span><span>470-390=80
80/2=40
The wind is 40 mph
What does find the speed of the wind in still air mean? The wind is not still air!
Do you mean find the speed of the wind or find the speed of the plane in still air? Try reading your post before clicking submit.
470-40=430
390+40=430
The plane in still air goes 430 mph
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Answer:
6r+10
Step-by-step explanation:
2 x 3r+2 x 5 = 6r +10
Answer:
<h2>x = -9 and x = -10</h2>
Step-by-step explanation:
