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lara [203]
3 years ago
6

Which algebic expression is ""ten less than a number divided by twelve""?

Mathematics
2 answers:
butalik [34]3 years ago
7 0

Answer:

N/12 -10

Step-by-step explanation:

AleksandrR [38]3 years ago
6 0

Answer:

StartFraction n Over 12 EndFraction minus 10 (A)

Step-by-step explanation:

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Which expression is equivalent to 10x²y + 25x^2
r-ruslan [8.4K]

Answer:

5x²(2y + 5)

Step-by-step explanation:

10x²y + 25x²

to start we have to express the parts of the function as multiplication

2*5*x²*y + 5*5*x²

then we have to see that they have both parts of the sum in common, and what they have in common we get out of common invoice and what is left we add together.

5x²(2y + 5)

6 0
3 years ago
4.
RUDIKE [14]

Answer:

least possible number of sweets = lowest common multiple of 5,6 & 10 - 2

-I hope this helps! I got it figured out until near like the very end.-

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5 0
3 years ago
This question is worth 100 points if you get this right.
stiv31 [10]

Answer:

it will take 7 nights

Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
7. Which coordinate lies in the solution set for
Nana76 [90]

Answer:

The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.

Step-by-step explanation:

See the graph attached to this question.

The solution of the set of inequalities is given by the shaded region on the graph.

Now, the point (0,5) is outside this shaded region, hence it can not be the solution.

The point (3,0) also is outside this shaded region, hence it can not be the solution.

The point (-3,0) also is outside this shaded region, hence it can not be the solution.

Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)

6 0
2 years ago
Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.
natta225 [31]

The ODE is linear:

y'=x^4-\dfrac yx

y'+\dfrac yx=x^4

Multiplying both sides by x gives

xy'+y=x^5

Notice that the left side can be condensed as the derivative of a product:

(xy)'=x^5

Integrating both sides with respect to x yields

xy=\dfrac{x^6}6+C

\implies y(x)=\dfrac{x^5}6+\dfrac Cx

Since y(1)=1,

1=\dfrac16+C\implies C=\dfrac56

so that

\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}

4 0
3 years ago
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