![\large\begin{array}{l} \textsf{Therefore, the domain of f is}\\\\ \mathsf{D_f=\{x\in\mathbb{R}:~~x\ne -7~~and~~x\ne 7\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_f=\mathbb{R}\setminus\{-7,\,7\}}\\\\\\ \textsf{or using the interval notation}\\\\ \mathsf{D_f=\left]-\infty,\,-7\right[\,\cup\,\left]7,\,+\infty\right[.} \end{array}](https://tex.z-dn.net/?f=%5Clarge%5Cbegin%7Barray%7D%7Bl%7D%20%5Ctextsf%7BTherefore%2C%20the%20domain%20of%20f%20is%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5C%7Bx%5Cin%5Cmathbb%7BR%7D%3A~~x%5Cne%20-7~~and~~x%5Cne%207%5C%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctextsf%7Bor%20using%20a%20more%20compact%20form%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5Cmathbb%7BR%7D%5Csetminus%5C%7B-7%2C%5C%2C7%5C%7D%7D%5C%5C%5C%5C%5C%5C%20%5Ctextsf%7Bor%20using%20the%20interval%20notation%7D%5C%5C%5C%5C%20%5Cmathsf%7BD_f%3D%5Cleft%5D-%5Cinfty%2C%5C%2C-7%5Cright%5B%5C%2C%5Ccup%5C%2C%5Cleft%5D7%2C%5C%2C%2B%5Cinfty%5Cright%5B.%7D%20%5Cend%7Barray%7D)
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Tags: <em>function domain real rational factorizing special product interval</em>
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Answer:
the answer to your question should be 2,068
Step-by-step explanation:
i hope i am right but i think so
Answer: C: 2/5
Step-by-step explanation:
because there is 10 tiles total in two bags with 5 tiles each
each bag has two vowels
so part over whole means 2/5
The equation for
the standard form of parabola is given as:
y = A (x - h)^2 +
k
with (h, k) being
the (x, y) coordinates of the vertex
For the given
problem, we are given that (h, k) = (5, - 12).
We can then use point (0, 63) for x and y to solve for A
63 = A (0 - 5)^2 - 12
75 = A (25)
A = 75 / 25
A = 3
Equation of given
parabola:
y = 3 (x - 5)^2 - 12
We can now solve for the x –intercept:
Set y = 0, then solve for x
0 = 3 (x - 5)^2 -
12
3 (x - 5)^2 = 12
(x - 5)^2 = 4
Taking sqrt of
both sides
x - 5= ±2
x = -2 - 5 = -7
and x = 2 - 5 = - 3
x = -3, -7
Answer:
x-intercepts of given parabola: -3 and -7
(-3, 0) and (-7,
0)
