i think its c lmk if i am wrong
It will reflect the same distance over the Y axis, from the right side of the graph to the left side of the graph.
(5460.4)(3/8) = 2,047.65 to savings
5460.4 - 2,047.65 = 3,412.75 checking
Answer:
The p value would be given by:
For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG
Step-by-step explanation:
Information given
represent the mean
represent the population standard deviation
sample size
represent the value to verify
represent the significance level for the hypothesis test.
z would represent the statistic
represent the p value
Hypothesis to test
We want to test if the true mean for this case is 46.7, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Since we know the population deviation the statistic is given by:
(1)
Replacing we got:
The p value would be given by:
For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG
Answer:
Option A.
; grows approximately at a rate of 0.4% daily
Step-by-step explanation:
we have

where
f(x) the number of weeds in the garden
x ----> the number of weeks
Calculate how quickly the weeds grow each day
Remember that a week is equal to seven days
so

Using the law of exponents
b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x
so
![f(x)=86[(1.29)^{\frac{1}{7}}]^{x}](https://tex.z-dn.net/?f=f%28x%29%3D86%5B%281.29%29%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D%5D%5E%7Bx%7D)
![f(x)=86[1.04]^{x}](https://tex.z-dn.net/?f=f%28x%29%3D86%5B1.04%5D%5E%7Bx%7D)
therefore
The rate is approximately
1.04=1+r
r=1.04-1=0.04=4% daily