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zalisa [80]
3 years ago
10

What is .4 as a percent??

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0
The answers would be 40%
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A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio
Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

7 0
3 years ago
Lim (x+1) (3x^2-9)<br> X2
mafiozo [28]

Answer:

\lim_{x \to 2} (x+1)(3x^2-9) = 9

Step-by-step explanation:

Step 1: Write out limit

\lim_{x \to 2} (x+1)(3x^2-9)

Step 2: Evaluate

(2 + 1)(3(2)² - 9)

3(3(4) - 9)

3(12 - 9)

3(3)

9

5 0
3 years ago
Why don't negative values of h and t make sense?
Anni [7]
It really depends what you're understanding or how the problem is set up.
5 0
4 years ago
Which expression has the fewest significant figures?
yanalaym [24]

Hello!

Here are some rules to determine the number of significant figures.

  1. Numbers that are not zero are significant (45 - all are sigfigs)
  2. Zeros between non-zero digits are significant (3006 → all are sigfigs)
  3. Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
  4. Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
  5. Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
  6. In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)

Now, let's find the number of significant figures in each given number.

A). 296.54

Since these digits are all <em>non-zero</em>, there are 5 significant figures.

B). 5003.1

Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.

C). 360.01

Again, the two zeros are between non-zero digits. There are 5 significant figures.

D). 18.3

All of these digits are non-zero, hence, there are 3 significant figures.

Therefore, expression D has the fewest number of significant figures being 3.  

4 0
3 years ago
Read 2 more answers
If 3t -7 = 5t, then 6t =
USPshnik [31]

Answer:

21

Step-by-step explanation:

3t-7=5t

subtract 3t from both sides

-7 = 2t

multiply both sides by 3

-21 = 6t

so 6t = -21

5 0
2 years ago
Read 2 more answers
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