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olya-2409 [2.1K]
3 years ago
12

A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio

n, how many red skittles can be expected in the box? Based on this information, how many red skittles can be expected in the box?
5 red skittles
7 yellow skittles
8 orange skittles
2 green skittles
3 purple skittles

Based on this information, how many red skittles can be expected in the box?
Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

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Step-by-step explanation:

Monomial = x^2, 1 term

Binomial = x^2 + x, 2 terms

Trinomial = x^2 + x + 3, three terms

Binomial is more than 3 terms

Let's do a 3rd degree polynomial like:

{x}^{3}  + 2x^{2}  + 4x + 8

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Now let's factor the second part, the 4x + 8. This can be factored by a 4.

4(x + 2)

Your new equation is:

\frac{( {x}^{2}  + 4)(x + 2)}{x - 2}

x^2 + 4 can be factored again down to (x + 2)(x + 2)

YOUR FINAL EQUATION IS:

\frac{(x + 2)(x + 2)(x + 2)}{x - 2}

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