Answer:
The diagonal of kite intersect at the point p is C. 68°
To find the area of a square, do base times height.
If it is a square then all the sides are equal. Take 12 and divide it by 4 to find out that each side is 4 feet.
Base-4
Height-4
(4)(4)=16
Here's our equation.

We want to find out when it returns to ground level (h = 0)
To find this out, we can plug in 0 and solve for t.


So the ball will return to the ground at the positive value of

seconds.
What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

Answer:
y=4
Step-by-step explanation:
Read off the graph. The corresponding y-coordinate when the x-coordinate is 7 is 4.