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Harlamova29_29 [7]

4 years ago

11

Find the constants m and b in the linear function f(x) = mx + b so that f(4) = 1 and the straight line represented by f has slop

e -14

1 answer:

HACTEHA [7]4 years ago

6 0

The equations is f(x)=-14x-55
m=-14
b=-55

I checked my answer by plugging in (4,1) which was given.

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BRAINLIEST AND MAX PTS<br><br> CONVERT y = 40x + 600 to point-slope form

IRISSAK [1]

Answer:

The answer to your question is y - 0 = 40(x - 15)

Step-by-step explanation:

y = 40x + 600

Convert to y - y₁ = m(x - x₁)

Process

1.- Factor 40 in the right side of the equation

y = 40(x - 15)

2.- Give the form of the point slope form

y - 0 = 40(x - 15)

where

y₁ = 0

m = 40

x₁ = 15

3 0

3 years ago

Read 2 more answers

Marcus monthly salary is $1,500 plus 10% of sales. How much could Marcus earn per month with salary and 9% sales? Please explain

sergejj [24]

If Marcus monthly salary is $1,500 plus 10% of sale, then he could earn 1500 + 0.09x per month with salary and 9% sales

Monthly salary of Marcus = $1500

The percentage incentives for sales = 10%

If the percentage of incentive for sales is 9 %

Consider the amount of sales is $x

Therefore the monthly salary of Marcus = Monthly salary of Marcus + (The amount of sales × 9/100)

Substitute the values in the equation

The monthly salary of Marcus = 1500 + (x×9/100)

Divide the numbers in the equation

= 1500 + (x × 0.09)

Multiply the numbers the numbers

= 1500 + 0.09x

Therefore, the monthly salary of Marcus will be 1500 + 0.09x

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8 0

1 year ago

Can someone please help I can’t understanddd.

dem82 [27]

Hello,

Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:

As

$f(x)=x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\\ \\(f\times g)(x)=\dfrac{3(x-4)(x-3)}{(x-4)(x+4)}=\dfrac{3x-9}{x+4}$

Thanks

6 0

3 years ago

For what value(s) of k is the trinomial x² + kx - 24 factorable?

Elza [17]

Answer:

.......................

4 0

3 years ago

Line XY bisects and is perpendicular to AB and CD. CD = 10 and XY = 24. What is the length of AP?

myrzilka [38]

Answer:

<u>AP = 13</u>

Step-by-step explanation:

See the attached figure.

CD = 10 and XY = 24

Line XY bisects and is perpendicular to AB and CD

∴ XY bisects at Y

∴ CY = 0.5 CD = 0.5 * 10 = 5

And from the geometry of the shape

P is the midpoint of XY

∴ XP = YP = 0.5 XY = 0.5 * 24 = 12

XY is perpendicular to CD

∴ ΔPYC is a right triangle at Y

∴ PC (hypotenuse) = $\sqrt{PY^2+YC^2} =\sqrt{12^2+5^2}=\sqrt{144+25} =\sqrt{169} =13$

From the figure AP = PC = 13

8 0

3 years ago