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Harlamova29_29 [7]

4 years ago

11

Find the constants m and b in the linear function f(x) = mx + b so that f(4) = 1 and the straight line represented by f has slop

e -14

1 answer:

HACTEHA [7]4 years ago

6 0

The equations is f(x)=-14x-55
m=-14
b=-55

I checked my answer by plugging in (4,1) which was given.

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The scale factor for a model is 5cm= m model: 9.5cm actual : 30.5m

MaRussiya [10]

We are given dimensions of model and actual figure.

model: 9.5cm actual : 30.5m.

We need to find the length of actual shape for the scale factor 5cm.

Let us assume actual length be x m.

Let us set a proportion now.

<h3>5 : x = 9.5 : 30.5</h3>

Let us convert proportion into fractions.

$\frac{5}{x}=\frac{9.5}{30.5}$

On cross multiplying, we get

9.5x = 5× 30.5

9.5x = 152.5.

On dividing both sides by 9.5, we get

$\frac{9.5x}{9.5}=\frac{152.5}{9.5}$

x=16.05.

<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>

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3 years ago

How i can prove the proofs?

Marianna [84]

You can prove the proofs by showing your work to prove the proofs.

3 0

3 years ago

Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company

erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that $n = 16$

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that $p = 0.5$

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0$

$P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002$

$P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018$

$P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105$

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0

3 years ago

Which box-and-whisker plot shows the high temperatures in Pittsburgh, Pennsylvania during the first two weeks of March: 33, 45,

nikitadnepr [17]

There is no picture so i am not sure what to tell u

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3 years ago

How much does 56 Fit into 7284

Vera_Pavlovna [14]

130

7284/56 = 130 (Rounded)

3 0

3 years ago