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PSYCHO15rus [73]
3 years ago
13

Find the dimensions of a rectangle with perimeter 60 m whose area is as large as possible. (if both values are the same number,

enter it into both blanks.)

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0
I am just doing this because I am niceyeah lol

Pavel [41]3 years ago
3 0

Answer: Area of rectangle = 225 square meter.

Explanation:

Since we have given that

Perimeter of rectangle = 60 m

Since we have also state that both the value of dimensions are equal to each other ,

Length = breadth

As we know the formula of perimeter of rectangle which is given as

2(Length+Breadth)=60\\\\Length+Breadth=\frac{60}{2}=30\\\\Length=Breadth=15\ m

So, Area of rectangle is as large as possible is given as

Length\times breadth=15\times 15=225\ m^2

Hence, area of rectangle = 225 square meter.

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The Perimeter of a rectangle is 194 cm. The length of the rectangle is three centimeters less than four times the size of width.
Rus_ich [418]
Given that:
Perimeter=194 cm
Width=w
Length, L= 4w-3
Formula for perimeter of rectangle:
P=2(L+W)
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194=2(5w-3)
Divide both sides by 2.
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So length= 4 (20) -3 = 80-3 =77 cm
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Answer: Length=77 cm and width=20 cm

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Answer:

5

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8 0
3 years ago
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Can you help me with these questions
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