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Lorico [155]
3 years ago
6

Is the sum of two integers always greater than the difference between them? Why or why not? Give examples to support your answer

.
Mathematics
1 answer:
crimeas [40]3 years ago
3 0
Let x and y be the two integers. 

The sum of the integers is x+y while the difference is x-y assuming x is larger than y. 

If x+y > x-y, then 

x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0

So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true

If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around

Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work. 

So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
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2/3 + 1/2 in simple form fractions
nata0808 [166]
Try and find the common denominator which is 6 since 2×3 is 6 then once u get ur denominator u have to find the numerator which would be 4/6+3/6 And that would equal 7/6 and if you would u would keep it like that but if u would have to change it into a mixed fraction it would be 1 and 1/6

Hoped this helped
3 0
3 years ago
What is the distance between coordinates (-6.25,5) and (-3.75,2)
Oksi-84 [34.3K]

Answer:

\sqrt{15.25}

Step-by-step explanation:

To find the distance, we can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} when the given points are (x_1,y_1) and (x_2,y_2)

Plug in the points (-6.25,5) and (-3.75,2)

d=\sqrt{(-6.25-x_1)^2+(5-y_1)^2}\\d=\sqrt{(-6.25-(-3.75))^2+(5-2)^2}\\d=\sqrt{(-6.25+3.75)^2+(5-2)^2}\\d=\sqrt{(-2.5)^2+(3)^2}\\d=\sqrt{6.25+9}\\d=\sqrt{15.25}

Therefore, the distance between the two coordinates is \sqrt{15.25}, or approximately 3.91.

I hope this helps!

6 0
3 years ago
You rode a bicyde for 2 hours and travelled 43 km, calculate your average<br>speed.​
cupoosta [38]

Answer:

22.5km per hour

Step-by-step explanation:

5 0
3 years ago
The perimeter of a rectangular field is 52 yards. The length is 4 more yards than the width. Find the length and width of the fi
hichkok12 [17]

:) Brainliest pls?

Answer:

D.

Width = 11 yards

Length = 15 yards

Step-by-step explanation:

P = 2(l + w)

Consider the width to be x.

The length would then be x+4.

We know that P = 52 yd

52 = 2(x + x + 4)

52 = 2(2x + 4)

52 = 4x + 8 (Subtract 8 from both sides)

44 = 4x (Divide both sides by 4)

x = 11

The width is x, so the width is 11 yards.

The length is x+4, so the length is 15 yards.

8 0
3 years ago
What is (3/5) squared?
Marat540 [252]
3/5 squared in 9/25, 3*3/5*5 :)
5 0
3 years ago
Read 2 more answers
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