Should be markdown, but if you have other options let me know and I'll tell you which it is. But if markdown is one of your choices, or if this is fill-in, it's markdown.
Volume of a spehere=(4/3)πr³
Data:
diameter=3.5 in
π=3.14
1)we calculate the radius:
r=diameter/2=3.5 in / 2=1.75 in
2) we calculate the volume of this sphere:
volume=(4/3)*3.14*(1.75 in)³=22.4379...in³≈22.44 in³.
Answer: 22.44 in³
The parabolic motion is an illustration of a quadratic function
The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
<h3>How to model the function?</h3>
Given that:
x stands for time and y stands for height in feet
So, we have the following coordinate points
(x,y) = (5,0), (11,0) and (10,80)
A parabolic motion is represented as:
y =ax^2 + bx + c
At (5,0), we have:
25a + 5b + c = 0
c= -25a - 5b
At (11,0), we have:
121a + 11b + c = 0
Substitute c= -25a - 5b
121a + 11b -25a - 5b = 0
Simpify
96a + 6b = 0
At (10,80), we have:
100a + 10b + c = 80
Substitute c= -25a - 5b
100a + 10b - 25a -5b = 80
75a -5b = 80
Divide through by 5
15a -b = 16
Make b the subject
b = 15a + 16
Substitute b = 15a + 16 in 96a + 6b = 0
96a + 6(15a + 16) = 0
Expand
96a + 90a + 96 = 0
This gives
186a = -96
Solve for a
a = -16/31
Recall that:
b = 15a + 16
So, we have:
b = -15 * 16/31 + 16
b =-240/31 + 16
Take LCM
b =(-240 + 31 * 16)/31
[tex]b =256/31
Also, we have:
c= -25a - 5b
This gives
c= 25*16/31 - 5 * 256/31
Take LCM
c= -880/31
Recall that:
y =ax^2 + bx + c
This gives
y = -16/31x^2 + 256/31x - 880/31
Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
Read more about parabolic motion at:
brainly.com/question/1130127
Answer:
8.0 seconds to the nearest tenth,
Step-by-step explanation:
h=-16t^2 +vt + c.
-16t^2 + 116t + 101 = 0
t = [ -116 + /- √(116^2 - 4*-16*101) ] / (-32)
t = (-116 +/- √19920) / (-32)
t = -0.79, 8.036 (we ignore the negative root)
The time in flight = 8.036 seconds.
