<span><span>9<span>(6j+2+j)</span></span><span>9<span>(6j+2+j)</span></span></span>Add <span><span>6j</span><span>6j</span></span> and <span>jj</span> to get <span><span>7j</span><span>7j</span></span>.<span><span>9<span>(7j+2)</span></span><span>9<span>(7j+2)</span></span></span>Apply the distributive property.<span><span>9<span>(7j)</span>+9⋅2</span><span>9<span>(7j)</span>+9⋅2</span></span>Multiply <span>77</span> by <span>99</span> to get <span>6363</span>.<span><span>63j+9⋅2</span><span>63j+9⋅2</span></span>Multiply <span>99</span> by <span>22</span> to get <span>1818</span>.<span>63j+<span>18</span></span>
Domain of f(x) = √6 - 2x is {x | -∞ < x ≤ 3}
On the bottom line, the 106 and number 1 make a straight line and needs to equal 180 degrees.
This means number 1 = 180-106 = 74 degrees.
Because x and y are parallel, the top outside angle is the same as number 1.
6x +8 = 74
Subtract 8 from both sides:
6x = 66
divide both sides by 6:
x = 66 / 6
x = 11
Now you have x, replace x in the equation for 7x-2 to find that angle:
7(11) -2 = 77-2 = 75 degrees.
The three inside angles need to equal 180 degrees.
Angle 2 = 180 - 74 - 75 = 31 degrees.
Answer:
<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>
Step-by-step explanation:
First alloy contains 34% copper and the second alloy contains 48% alloy.
We wish to make 46 pounds of a third alloy containing 37% copper.
Let the weight of first alloy used be 
in pounds and the weight of second alloy used be 
in pounds.
Total weight = 
Total weight of copper = 
Subtracting 34 times first equation from second equation,
∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.
