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atroni [7]
3 years ago
7

Laura has $720 and saves $30 a week. Taylor has $1200 and spends $30 a week. in how many weeks will Taylor and Laura have the sa

me amount of money? how much money will that be?
Mathematics
1 answer:
Setler79 [48]3 years ago
4 0
Let w = number of weeks.

In week w,
Laura has: 720 + 30w
Taylor has: 1200 - 30w

Set the two amounts equal and solve for w, the number of weeks.

720 + 30w = 1200 - 30w

60w = 480

w = 8

They will have the same amount of money in 8 weeks.

Laura will have in 8 weeks:
720 + 30w = 720 + 30 * 8 = 720 + 240 = 960

Taylor will have in 8 weeks:
1200 - 30w = 1200 - 30 * 8 = 1200 - 240 = 960

They will both have $960 in 8 weeks.
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An ion has a charge of +7. How far is it from being neutral?
rusak2 [61]

Answer:

The answer is B. -7

Step-by-step explanation:

the -7 cancels out the +7 which makes it neutral

6 0
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Fifty balls are numbered 1 to 50 and a red dot is painted on those balls that are a multiple of 6. The balls are mixed into a ba
djyliett [7]

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Step-by-step explanation:

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7 0
3 years ago
Solve the inequality 2x−y⩾−5 for y. Which inequality represents the inequality in slope-intercept form?
aleksandr82 [10.1K]

Answer:

y\leq 2x+5

This represents slope intercept form: y = mx + b

Step-by-step explanation:

2x - y \geq -5\\2x+5\geq y

4 0
3 years ago
A car is merging onto a freeway (beginning at rest), accelerating at a constant rate of 10ft/sec2. How long does it take to reac
masha68 [24]

Answer:

<h2>10.3seconds</h2>

Step-by-step explanation:

Step one:

given data

acceleration,a= 10ft/sec^2

final velocity v= 70mph

first, let is convert mph to ft/sec

1mph is 1.46667 ft/sec

70 mph is x

cross multiply we have

x= 102.7ft/s

Step two:

we are using the first equation of motion

v=u+at

initial velocity u= 0m/s

102.7=0+10*t

102.7=10t

divide both sides by 10

t=10.3seconds

5 0
3 years ago
18. Let f be a function with domain the set of all real numbers and having the following
Mashcka [7]

The derivative of the given function is f'(x) = k f(x) where k= \lim_{h \to 0} \frac{f(h)-1}{h}.

<h3>What is the derivative of a function?</h3>

Let f be a function defined on a neighborhood of a real number a. Then f is said to be differentiable or derivable at 'a' if \lim_{x \to a} \frac{f(x)-f(a)}{x-a} exists finitely. The limit is called the derivative or differential coefficient of f at 'a'. It is denoted by f'(a).

If f is differentiable at 'a', then

f'(a) = \lim_{h\to 0} \frac{f(a+h)-f(a)}{h}

<h3>Calculation:</h3>

The given properties are:

(i) f(x + y) = f(x)f(y) for all real numbers x and y.

(ii) \lim_{h \to 0} \frac{f(h)-1}{h} = k; where k is a nonzero real number.

Then, the derivative of the function f(x) is,

f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

From property (i), f(x + h) = f(x)f(h)

On substituting,

f'(x) = \lim_{h \to 0} \frac{f(x)f(h)-f(x)}{h}

      = \lim_{h \to 0} \frac{f(x)[f(h) - 1]}{h}

From property (ii), \lim_{h \to 0} \frac{f(h)-1}{h} = k;

f'(x) = \lim_{h \to 0} \frac{f(x)[f(h) - 1]}{h}

      = f(x). \lim_{h \to 0} \frac{f(h)-1}{h}

      = f(x). k

      = kf(x)

Therefore, f'(x) = k f(x); where f'(x) exists for all real numbers of x.

Learn more about the derivative of a function here:

brainly.com/question/5313449

#SPJ9

6 0
2 years ago
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