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mariarad [96]
2 years ago
6

Solve the inequality 2x−y⩾−5 for y. Which inequality represents the inequality in slope-intercept form?

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
4 0

Answer:

y\leq 2x+5

This represents slope intercept form: y = mx + b

Step-by-step explanation:

2x - y \geq -5\\2x+5\geq y

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T/8 + 23 - 4 = 36. Solve for the variable. Write the answer only, do not type in T= form.
oksian1 [2.3K]
136 is the answer!!!!
6 0
2 years ago
Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv
mestny [16]

Answer:

  • B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

Step-by-step explanation:

<u>Graph of the function:</u>

  • y = -√x + 1

The domain is x ≥ 0, the range y ≤ 1

Correct answer choice is B

  • On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

<em>The graph is attached</em>

7 0
3 years ago
Read 2 more answers
Find the area of the following ellipse. a = 4.5 m; b = 5.5 m
LenaWriter [7]

Answer:

Area of ellipse is ≈ 77.78 m^{2}

Step-by-step explanation:

Given the dimension of ellipse

  a = 4.5 m

  b = 5.5 m

Now, Area of ellipse = \pi ab

                                  = \frac{22}{7}\times 4.5\times 5.5

                                  = \frac{5445}{70}

                                  = 77.78 m^{2}

Hence Area of ellipse will be 77.78 m^{2}

6 0
3 years ago
Read 2 more answers
Which explains why the graph is not a function?
iren2701 [21]

Answer:

can post a picture of the question?

4 0
3 years ago
A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho
Mice21 [21]

Answer:

3.8 seconds

Step-by-step explanation:

Given equation

h= -16t^2 + 60t + 5

When the ball hits the ground then height is 0

So we replace h with 0 and solve for t

0= -16t^2 + 60t + 5

a= -16 , b= 60 and c= 5

Apply quadratic formula to solve for t

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

=\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}

=\frac{-60+-28\sqrt{5}}{-32}

=\frac{4(-15+-7\sqrt{5})}{-32}

=\frac{(-15+-7\sqrt{5})}{-8}

Now make two fractions and solve for x

t= -\frac{7\sqrt{5}-15}{8}=-0.0815

t= \frac{7\sqrt{5}+15}{8}=3.83

So answer is 3.8 seconds


4 0
2 years ago
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