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Andru [333]
3 years ago
8

Can someone help me with this problem? Please

Mathematics
1 answer:
Molodets [167]3 years ago
4 0
Semicircle g has center at (-4,0) and radius 2.

Use the general equation for a circle:

(x-h)^2 + (y-k)^2 = r^2

Here, the center is (h,k), where h = -4 and k=0.  Also, r = 2

So we have (x-[-4])^2 + (y-0)^2 = r^2 = 4

Let's solve for y in terms of x:

y^2 = 4 - (x+4)^2 

Since we are interested in only the bottom half of this circle,

y  =  - sqrt(4 - x^2 - 8x - 16)
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Please help asap 25 pts
natulia [17]

Answer:

C and D

Step-by-step explanation:

in equations y=4x+9 and y=4x-9 you have the same slope (4) so paralleling is guaranteed.

y=9 and y=18 you can understand as y=0x+9 and y=0x+18, so in this situation you have the same slope (0), so lines y=9 and y=18 are parallel too.

5 0
3 years ago
Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AB = 8
Delicious77 [7]

Answer:

x = 32

Step-by-step explanation:

∠BCA = ∠DBA (90 - ∠DBC)

∠A = ∠A

ΔABD similar to ΔACB

AC/AB = AB/AD

x / 8 = 8 / 2

x = 32

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3 years ago
If 68 is 40% of a value, what is the value?
Anika [276]
60 divided by 0.4(40%)=150

=150
8 0
3 years ago
Read 2 more answers
18°+2, what is the value of y?
Travka [436]

Answer:

Were is y located at?

Step-by-step explanation:

5 0
3 years ago
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0
3 years ago
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