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Verizon [17]
3 years ago
5

The elevation of city A is 72 feet above sea level; the elevation of city C is 24 feet above sea level. The elevation of city D

is 1 over 4 of the elevation of city C.
Part A: Write an expression to represent the elevation, in feet, of city D. (5 points)

Part B: Simplify the expression and explain why the answer is negative or positive. (5 points)
Mathematics
2 answers:
Anettt [7]3 years ago
6 0
Part A :
D = (1/4) * C D = 1/4 * 24 D = 24/4 = 6 ft above sea level
Part B :
Your answer is positive because D is still above sea level...if it would have been below sea level, then it would have been negative
kari74 [83]3 years ago
4 0

Answer:

Part A :

D = (1/4) * C D = 1/4 * 24 D = 24/4 = 6 feet above sea level

Part B :

Your answer is positive because D is still above sea level. If it would have been below sea level, then it would have been negative .

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A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)
Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

36^6

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Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

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So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

P(A)=P(B)=\dfrac{5}{36}

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8

exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8

ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8

oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8

uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}

Finally, you can compute the probability of the union using the formula

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Since we already computed all these quantities.

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3 years ago
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