The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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To answer this first we set up a proportion and then solve. Lets do it:-

Cross Multiply:-
80 · 4 = 320
Divide:-
420 ÷ 12 = 60
So, 180 ears of corn are for
$60.Hope I helped ya!!
If 5 x 6 = 30 you can figure out 8 x 6 by adding 6 three times to 30!
30 + 6 = 36
36 + 6 = 42
42 + 6 = 48 <-- the answer is 48!
Answer:
74
Step-by-step explanation:
Answer:
none of the above im pretty sure
Step-by-step explanation: