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sveta [45]
3 years ago
8

A certain stock starts the day at $273/8 per share. If it drops $21/2 during the day, what is its closing value? A. $247/8 B. $2

57/8 C. $241/8 D. $251/8 Mark for review (Will be highlighted on the review page)
Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

A. $ 24 7/8

Step-by-step explanation:

GIVEN: A stock starts the day at $27 3/8 per share.

             Share drops $2 1/2 during the day.

To Find : Closing value

Solution : first we need to find how many 1/8 are there in 1/2

So, \frac{\frac{1}{2} }{\frac{1}{8} } =4

when share drops by $2 then  share will be :

$27 - $2 =$25


and \frac{3}{8} - 4(\frac{1}{8})


⇒\frac{3}{8} - \frac{4}{8}


⇒\frac{-1}{8}


So, 25-\frac{1}{8}


⇒24\frac{7}{8}

So, its closing value is 24\frac{7}{8}.

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The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

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Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

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Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

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brainly.com/question/27683633

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3 0
1 year ago
A farm stand sold 12 ears of corn for 4$ .the farm stand sold 180 ears of corn at the same rate
oksano4ka [1.4K]
To answer this first we set up a proportion and then solve. Lets do it:-

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Cross Multiply:-

80 · 4 = 320

Divide:-

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So, 180 ears of corn are for $60.

Hope I helped ya!! 
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