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2 years ago

The circular opening of a tunnel has a circumference of 36 meters. What is the diameter of the tunnel?

1 answer:

7 0

C=2(3.14159...)R
You’re given the circumference, so all you need to do is plug that in and simplify.
36=2(3.14159...)R
36=6.28R
36/6.28=R
R is about 5.73

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State whether f is a function

Alenkinab [10]

<h2>Answer:</h2>

$y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function$

<h2>Step by step solution:</h2>

A function $f$ from a set $A$ to a set $B$ is a relation that assigns to each element $x$ in the set $A$ exactly one element $y$ in the set $B$ . The set $A$ is the domain (also called the set of inputs) of the function and the set $B$ contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function $f$ has an inverse function if and only if there is no any horizontal line that intersects the graph of $f$ at more than one point. So the function is called one-to-one. The graph of $f$ is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find $f^-{1}(x)$ :

$f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}$

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

5 0

2 years ago

Read 2 more answers

If the diameter of the clock face is 10 inches, what is the radius? Explain your answer.

Bumek [7]

Answer:

the radius is 5 inches

Step-by-step explanation:

dimeter is twice the radius or radius is half of diameter

7 0

2 years ago

1) A shirt went from $8 to $10.

bagirrra123 [75]

Answer:

1) 20% change I think its an increase.

If needed I could try to answer the 2nd question but I am sure that I got the first one right.

Step-by-step explanation:

7 0

2 years ago

What is an expression that equals 1 using the numbers 6, 3, and 5 only once

Gennadij [26K]

Answer: 1 = 6 - 5 + 3 × 0

8 0

2 years ago

What is the equation written in vertex from of a parabola with a vertex of (4, –2) that passes through (2, –14)?

vichka [17]

Answer:

y = -3(x - 4)² - 2

Step-by-step explanation:

Given the vertex, (4, -2), and the point (2, -14):

We can use the vertex form of the quadratic equation:

y = a(x - h)² + k

Where:

(h, k) = vertex

a = determines whether the graph opens up or down, and it also makes the parent function wider or narrower.

positive value of a = opens upward
negative value of a = opens downward
a is between 0 and 1, (0 < a < 1) the graph is wider than the parent function.
a > 1, the graph is narrower than the parent function.

h = determines how far left or right the parent function is translated.

h = positive, the function is translated h units to the right.
h = negative, the function is translated |h| units to the left.

k determines how far up or down the parent function is translated.

k = positive: translate k units up.
k = negative, translate k units down.

Now that I've set up the definitions for each variable of the vertex form, we can determine the quadratic equation using the given vertex and the point:

vertex (h, k): (4, -2)

point (x, y): (2, -14)

Substitute these values into the vertex form to solve for a:

y = a(x - h)² + k

-14 = a(2 - 4)² -2

-14 = a (-2)² -2

-14 = a4 + -2

Add to to both sides:

-14 + 2 = a4 + -2 + 2

-12 = 4a

Divide both sides by 4 to solve for a:

-12/4 = 4a/4

-3 = a

Therefore, the quadratic equation inI vertex form is:

y = -3(x - 4)² - 2

The parabola is downward-facing, and is vertically compressed by a factor of -3. The graph is also horizontally translated 4 units to the right, and vertically translated 2 units down.

Attached is a screenshot of the graph where it shows the vertex and the given point, using the vertex form that I came up with.

Please mark my answers as the Brainliest, if you find this helpful :)

8 0

2 years ago