Answer: Ix - 950°C I ≤ 250°.
Step-by-step explanation:
Ok, the limits are:
700°C to 1200°C.
The first step is to find the mean these numbers:
M = (700°C + 1200°C)/2 = 950°C
Now let's find the distance between the mean and the limits (which is equal to half the difference between our numbers)
D = (1200°C - 700°C)/2 = 250°C.
Now we can write our relation as:
Ix - MI ≤ D
Ix - 950°C I ≤ 250°.
if x = 1200°C.
I1200°C - 950°CI = 250°C ≤ 250°C ---- true.
if x = 700°C
I700°C - 950°CI = I-250°CI = 250°C ≤ 250°C ---- true
Base on the total area of the square garden and the number of plants planted on it, the area of the zucchini section is 15 feet²
<h3>How to find area of zucchini section?</h3>
Side Length of the square garden = 8 feet
Area of the garden = side length ²
= 8 feet × 8 feet
= 64 feet²
Flower portion:
Side Length = 2 feet
Area of flower portion = side length ²
= 2 feet × 2 feet
= 4 feet²
Remaining space = Area of the garden - Area of flower portion
= 64 feet² - 4 feet²
= 60 feet²
Remaining space is divided into 4 equal sections
= 60 feet² / 4
= 15 feet²
Therefore,
Tomatoes section = 15 feet²
Onions section = 15 feet²
Zucchini section = 15 feet²
Pepper section = 15 feet²
Learn more about area of a square:
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Answer:
yes
Step-by-step explanation:
Given the 2 equations
y = x + 6 → (1)
y = - x + 5 → (2)
Substitute y = x + 6 into (2)
x + 6 = - x + 5 ( add to both sides )
x + 6 = 5 ( subtract 6 from both sides )
x = - 1 ( divide both sides by )
x = = - ← one solution
The distribution shape that tells us for which it is best to use the mean is the skewed.
<h3>What is the mean?</h3>
This is the term that is used to refer to the average score that exists in a data set.
In the question, these are the reasons why the other options are not correct
When we say Bimodal we are talking about the 2 modes that are in a symmetric distribution. This has nothing to do with the mean
The bell shape has to do with how the normal distribution is when it is drawn. It would create a bell shape hence the mean is not useful.
symmetric has to do with the fact that there are mirror images when the vertical line is drawn in the distribution.
Uniformed shapes tells us that the classes are made up of the same frequency all through.
The skewed shape is what tells us if the median is more or if it is less.
Hence we have the answer that the distribution shapes for which it is most often appropriate to use the mean is the skewed.
Read more on the mean here
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Answer:
2/3 b +1/3 a
Step-by-step explanation:
b+ 1/3(-b+a)
= b - 1/3b + 1/3a
= 2/3 b +1/3 a
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