Answer:
Step-by-step explanation:
so when you post your picture you wanna click the thing that looks like a paper clip and attach a file or picture. or your can copy your photo and paste it in your question if you dont know how to take a picture just screenshot it *depends what kind of computer your using*
The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
Answer:
The formula for the area of the triangle is:

When <em>x</em> = 3, the area is 216 square centimeters.
When <em>x </em>= 2.4, the area is 138.24 square centimeters.
And when <em>x</em> = 5, the hypotenuse of the triangle is 50 centimeters.
Step-by-step explanation:
We are given a right triangle with a height of 8<em>x</em> and a base of 6<em>x</em>.
The area of a triangle is given by the formula:

So, by substitution:

When <em>x </em>= 3, the area will be:

And when <em>x</em> = 2.4, the area will be:

When <em>x </em>= 5, the height will be 8(5) = 40 cm and the base will be 6(5) = 30 cm.
By the Pythagorean Theorem:

So:

The hypotenuse will be:

Answer:
(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
(b) Every function of the form
is an antiderivative of 8x
Step-by-step explanation:
A function <em>F </em>is an antiderivative of the function <em>f</em> if

for all x in the domain of <em>f.</em>
(a) If
, then
is an antiderivative of <em>f </em>because

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.
(b) Because

then
is an antiderivative of
. Therefore, every antiderivative of 8x is of the form
for some constant C, and every function of the form
is an antiderivative of 8x.
Answer: 0.11429 (Rounded to fifth decimal place)