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Nookie1986 [14]

3 years ago

6

What’s the slope of the line in the graph?

1 answer:

zloy xaker [14]3 years ago

5 0

Check the picture below, let's use those two points on the line to get its slope.

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{0}}}\implies \cfrac{2}{2}\implies 1$

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When a graphed line is vertical, it indicates that the relation is ?

GuDViN [60]

Answer:When a vertical line is placed across the plot of this relation, it intersects the graph more than once for some values of x. If a graph shows two or more intersections with a vertical line, then an input (x-coordinate) can have more than one output (y-coordinate), and y is not a function of x.

Step-by-step explanation:

6 0

3 years ago

Rectangle JKLM is rotated 90° clockwise about the origin.

shusha [124]

Answer:

Clockwise rotation 90 ° about origin

R_{90, clockwise, origin}(x,y) -> (y,-x)

J(-4,1) therefore

R_{90, clockwise, origin}J(-4,1) -> J'(1,+4) this answer was form other person credits to him/her

Step-by-step explanation:

4 0

3 years ago

The container that holds the water for the football team is 1/2 full. after pouring in 9 gallons oo water, it is 4/5 full. how m

OLEGan [10]

.5x + 9 = .8x
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8 0

3 years ago

Explain your work !!!!<br> What is 17^3<br><br> A. 20<br> B. 4913<br> C. 51<br> D. 306

Travka [436]

A number raised to an exponent is that number multiplied by itself that number of times.

17^3 = 17 x 17 x 17 = 4913

The answer is B.

4 0

3 years ago

Read 2 more answers

A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies

RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean weight = 733 grams

$\sigma$ = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

P(X > x) = 0.05 {where x is the required weight}

P( $\frac{X-\mu}{\sigma}$ > $\frac{x-733}{9}$ ) = 0.05

P(Z > $\frac{x-733}{9}$ ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

$\frac{x-733}{9}=1.645$

${x-733}}=1.645\times 9$

$x = 733 + 14.81$

x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0

3 years ago