Answer:
A. The ordered pair (5, 3.5) represents 5 lbs. of strawberries cost $3.50.
B. The cost per pound of strawberries is shown at (1, 0.7).
C. The relationship shown in the graph is a direct variation because as the pounds of strawberries increase, the cost also increases.
Explanation:
A. The coordinate is in (x,y). The x-axis represents the pound of strawberries and the y-axis represents the cost of the strawberries.
B. The cost for one pound of strawberries can be calculated to find the exact value of y (cost) when x is 1. The graph shows 5 lbs. of strawberries cost $3.50 so divide $3.50 by 5 lbs. to find the cost per pound of strawberries. 3.5 ÷ 5 = 0.7. On the graph, the cost for one pound of strawberries is at (1, 0.7)
C. A direct variation in a graph is shown when both x and y increase or decrease together. In this case, as the pounds of strawberries increase, the cost of the strawberries also increases.
The volume of the tank is (70 cm)³ = 343,000 cm³.
Now,
1 mL = 1 cm³
1 L = 1000 mL
so we convert the given rate to

Then the time it will take to fill up the tank is

Answer:
consecutive = x+x+2
x+x+2 = 4x-20
2x+2=4x-20
2=2x-20
22=2x
x=11
Numbers are 11,13.
Hope this helps plz hit the crown :D
Explanation
Problem #2
We must find the solution to the following system of inequalities:

(1) We solve for y the first inequality:

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

The solution to this inequality is the set of all the points (x, y) over the line:

This line has:
• slope m = 3/2,
,
• y-intercept b = -2.
(2) We solve for y the second inequality:

The solution to this inequality is the set of all the points (x, y) below the line:

This line has:
• slope m = -1/3,
,
• y-intercept b = 2.
(3) Plotting the lines of points (1) and (2), and painting the region:
• over the line from point (1),
,
• and below the line from point (2),
we get the following graph:
Answer
The points that satisfy both inequalities are given by the intersection of the blue and red regions: