Question

The length of a rectangle is 3 feet more than twice the width. The perimeter is 128 feet. Find the length and width.

Answer 1

We are going to consider a rectangle with length called "a" and width "b"  Then we know that perimeter is the sum of both sides 2*a + 2*b = 128  And also the following equation given by the question: a = 2*b + 3  So solving the first equation: 2*(2*b+3) + 2*b = 128 4*b+6+2*b=128 6*b = 122 b = 122/6 = 61/3  Then a=2*122/6+3 = 244/6+3 = 262/6 = 131/3  Solution:  Length = 131/3 Width = 61/3