The length of a rectangle is 3 feet more than twice the width. The perimeter is 128 feet. Find the length and width.

1 answer:

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We are going to consider a rectangle with length called "a" and width "b" Then we know that perimeter is the sum of both sides 2*a + 2*b = 128 And also the following equation given by the question: a = 2*b + 3 So solving the first equation: 2*(2*b+3) + 2*b = 128 4*b+6+2*b=128 6*b = 122 b = 122/6 = 61/3 Then a=2*122/6+3 = 244/6+3 = 262/6 = 131/3 Solution: Length = 131/3 Width = 61/3

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