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snow_tiger [21]
3 years ago
15

All 136 students in the Math Club went on a field trip. Some students rode in vans which hold 8

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0
Answer: 3 buses, 2 vans
Explanation: let x be number of buses, y be number of vans,
136= 40x+8y
5=x+y
Use simultaneous equation,
136-8(5)= 40x +8y - 8(x+y)
96= 32x
x = 3
When x=3, y= 2
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I lost:
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Javier is purchasing a bouquet of roses from a floral shop. He wants the bouquet to have at least 12 roses but wants to spend le
Umnica [9.8K]

Answer: x+y\geq12

2.75x+3.50y\leq35

Step-by-step explanation:

Let x represents the number of red roses and y represents the number of white roses.

Given : Javier is purchasing a bouquet of roses from a floral shop. He wants the bouquet to have at least 12 roses.

i.e. the required inequality for this statement will be :-

No. of red roses +No. of white roses ≥ 12

i.e. x+y\geq12

Also, Red roses cost $2.75 each and white roses cost $3.50 each and he wants to spend less than $35.

i.e. $2.75(No. of red roses)+$3.50(No. of white roses)≤ $35

i.e. 2.75x+3.50y\leq35

Now, From (1) and (2) the system of inequalities represents the situation :

x+y\geq12

2.75x+3.50y\leq35

8 0
3 years ago
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F(x) = x2 + 1 g(x) = 5 – x (f – g)(x) =
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Answer:

x^2+x-4

Step-by-step explanation:

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This is a mathematics problem​
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) Consider the following probability density function of the random variable X. f(x) = k(2x + 3x2 ), 0 ≤ x ≤ 2. (i) Determine th
julia-pushkina [17]

I assume f(x)=0 otherwise. If f(x) is indeed a proper PDF, then its integral over the support of X is 1.

\displaystyle \int_{-\infty}^\infty f(x) \, dx = k \int_0^2 (2x + 3x^2) \, dx = 1

Compute the integral.

\displaystyle \int_0^2 (2x + 3x^2) \, dx = (x^2 + x^3)\bigg|_{x=0}^{x=2} = (2^2 + 2^3) - (0^2 + 0^3) = 12

Then

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