Check the picture below.
notice the sides, now, on the second triangle, side 6 slants a bit more to fit in 13, on the third triangle, side 6 slants even further to fit 13 in, now, if 6 were to slant completely, it'll make a flat-line with side 5, and there will be a triangle no more.
but even if side 6 would stretch to a flat-line, 5+6 is just 11, whilst side 13 is longer than that, so no dice.
Answer:
Step-by-step explanation:
we would like to expand the following logarithmic expression:
remember the multiplication logarithmic indentity given by:
so our given expression should be
by exponent logarithmic property we acquire:
hence, our answer is A
Answer:
It'll take him 1/4 hours to decorate the two signs.
Step-by-step explanation:
In order to know how long Roberto will take to decorate all the signs we need to find their surface area, since they're rectangular their area is given by the product of their dimensions.
First sign:
area1 = (2/3)*(1/4) = 2/12 = 1/6 foot²
Second sign:
area2 = (1/2)*(1/3) = 1/6 foot²
The total area he has to paint is the sum of their individual areas, so we have:
total area = area1 + area2 = 1/6 + 1/6 = 2/6 = 1/3 foot²
To find out how long he'll take to decorate this area we can use a rule of three as shown bellow:
3/4 hour -> 1 foot²
x hour -> 1/3 foot²
x = (3/4)*(1/3) = 1/4 hours
Answer:
2 cm per hour
Step-by-step explanation:
1 hour lines up with 2cm
2 hours line up with 4cm
3 hours line up with 6cm
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
