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Tatiana [17]
3 years ago
12

Anthony observes that when people are leaving class, about 50% turn left and about 50% turn right. Anthony wants to estimate the

probability that fewer than 3 of the first 4 students will turn left when leaving class tomorrow. To do this, he lets H represent turning left when leaving class and T represent turning right. He then flips a coin 4 times, recording the results. He repeats this process for a total of 20 trials. HHTT THHT HTTT HTHH HHTT HTHT THTH TTHH HHHH HTTH HHHT TTHT THHH THTH HHTT HTTT HTTH HHTT HTHH HHTH Drag and drop the correct fraction to the box to estimate the probability, using this simulation. Estimated probability that fewer than 3 of the first 4 students leaving class tomorrow will turn left:
Mathematics
1 answer:
Viktor [21]3 years ago
6 0
The probability is 7/10.

There are 14 outcomes in this simulation with fewer than 3 left turns, out of 20 times the simulation was run:
14/20 = 7/10
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1/7 divided by _____ = 14
Arlecino [84]

Answer:

1/7 divided by 1/98 will give you 14

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3 years ago
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Which value is equivalent to 2 x 3 + 4 -
Kisachek [45]
D. Always do multiplication first. 2×3 is 6, and 6+4 is 10.
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3 years ago
An endpoint of a line segment is (4,5) and the midpoint of the line segment is (3, -2). Find the other endpoint.
Dimas [21]

Answer:

(-8,1)

Step-by-step explanation:

Using the equation for midpoints we can find:

\frac{(5+y)}{2} =3,  \frac{(4+x)}{2} =-2

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y=1, x=-8

sry it's backwards

(-8,1)

Hope this helps!

4 0
3 years ago
Let the sample space be S = 1, 2 ,3 , 4, 5, 6 suppose those outcomes are equally likely. Compute the probability of the event E
Mekhanik [1.2K]

Given:

Sample space be S = 1, 2 ,3 , 4, 5, 6.

The outcomes are equally likely.

To find:

The probability of the event E ="an even number".

Solution:

We have,

Sample space is S = 1, 2 ,3 , 4, 5, 6.

So, the total number of outcomes is 6.

E ="an even number".

E = {2,4,6}

So, the total number of favorable outcomes is 3.

The probability of the event E is

P(E)=\dfrac{Favorable outcomes}{Total outcomes}

P(E)=\dfrac{3}{6}

P(E)=\dfrac{1}{2}

P(E)=0.5

Therefore, the probability of the event E is 0.5.

3 0
3 years ago
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