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Tatiana [17]
3 years ago
12

Anthony observes that when people are leaving class, about 50% turn left and about 50% turn right. Anthony wants to estimate the

probability that fewer than 3 of the first 4 students will turn left when leaving class tomorrow. To do this, he lets H represent turning left when leaving class and T represent turning right. He then flips a coin 4 times, recording the results. He repeats this process for a total of 20 trials. HHTT THHT HTTT HTHH HHTT HTHT THTH TTHH HHHH HTTH HHHT TTHT THHH THTH HHTT HTTT HTTH HHTT HTHH HHTH Drag and drop the correct fraction to the box to estimate the probability, using this simulation. Estimated probability that fewer than 3 of the first 4 students leaving class tomorrow will turn left:
Mathematics
1 answer:
Viktor [21]3 years ago
6 0
The probability is 7/10.

There are 14 outcomes in this simulation with fewer than 3 left turns, out of 20 times the simulation was run:
14/20 = 7/10
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3 years ago
Read 2 more answers
The ratio of the volume of soda in glass A to the volume of glass B is 8/3 to 7/2
MrRa [10]

Answer:

Total volume in the two glasses is 740 mL.

Step-by-step explanation:

Given:

Ratio of the volume of soda in glass A to the volume of glass B  =   8/3 : 7/2

Volume of soda in glass A = 320mL

To Find :

The total volume in the two glasses = ?

Solution:

Let the volume of soda in  glass B  be x

then

\text{ratio of soda in glass A} \times \text{ the volume of soda in glass B} = \text{ratio of soda in glass B} \times \text{ the volume of soda in glass A}

Substituting the values ,

\frac{8}{3} \times x  = \frac{7}{2} \times 320

\frac{8}{3} \times x  = \frac{2240}{2}

\frac{8}{3} \times x  = 1120

x  = 1120 \times \frac{3}{8}

x  = \frac{3360}{8}

x = 420

Now  total volume of soda in the two glasses

=> volume of soda in glass A + volume of soda in glass B

=> 320 + 420

=>740mL

5 0
3 years ago
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