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Nezavi [6.7K]
3 years ago
9

I need some help with this problem, I am supposed to solve for x

Mathematics
1 answer:
harina [27]3 years ago
3 0
I havnt done that in a while but I think you do x+105=x+95 then you add your like terms which would turn into 10=2x then you divide 10 divided by 2 which is 5, SO YOUR ANSWER IS (I think) 5x
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What is the solution to the system of equations?<br> x=3y+5<br> x-4y=3
vfiekz [6]

<span>Solve </span><span><span>x=<span><span>3y</span>+5</span></span>;<span><span>x−<span>4y</span></span>=3

</span></span><span><span>x=<span><span>3y</span>+5</span></span>;<span><span>x−<span>4y</span></span>=3</span></span>Step: Solve <span>x=<span><span>3y</span>+5</span></span>for x:Step: Substitute <span><span>3y</span>+5 </span>for x in <span><span><span>x−<span>4y</span></span>=3</span>:</span><span><span>x−<span>4y</span></span>=3</span><span><span><span><span>3y</span>+5</span>−<span>4y</span></span>=3</span><span><span><span>−y</span>+5</span>=3 </span>Simplify both sides of the equation<span><span><span><span>−y</span>+5</span>+<span>−5</span></span>=<span>3+<span>−5 </span></span></span>Add -5 to both sides<span><span>−y</span>=<span>−2</span></span><span><span><span>−y</span><span>−1</span></span>=<span><span>−2</span><span>−1 </span></span></span>Divide both sides by -1<span>y=2</span>Step: Substitute 2 for y in <span><span>x =<span><span>3y</span>+5</span></span>:</span><span>x=<span><span>3y</span>+5</span></span><span>x=<span><span><span>(3)</span><span>(2)</span></span>+5</span></span><span>x=11 </span>Simplify both sides of the equationAnswer:<span><span>x=<span><span>11<span> and </span></span>y</span></span>=<span>2</span></span>
8 0
2 years ago
Drone INC. owns four 3D printers (D1, D2, D3, D4) that print all their Drone parts. Sometimes errors in printing occur. We know
USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

8 0
3 years ago
What is a name for a symbol like +, -, ∙ or ÷?
Radda [10]
+ is positive, or plus
- is negative, or minus
the third one is multiply, can look like * and "x"
the fourth one is divide, can look like "/"

hope this helps
8 0
3 years ago
Read 2 more answers
B. If some amount of water contains 1400 oxygen atoms, how many hydrogen atoms does it contain?
Genrish500 [490]

Answer:

B: 2800 hydrogen atoms

C: 6760 hydrogen atoms

D: y=amount of oxygen atoms*2

Step-by-step explanation:

B: We know the formula for water is H2O. SO that means that there is 2 hydrogen atoms and 1 oxygen atom. So there is 2 times the amount of hydrogen atoms so we can do 1400*2=2800, So there is 2800 hydrogen atoms in the water.

C: Same thing as B. 3380*2=6760

D: y=amount of oxygen atoms*2. Because there is one oxygen atom and two hydrogen atoms so 1*2=2.

5 0
3 years ago
Find the measure Of PR
Misha Larkins [42]

Answer:

18

Step-by-step explanation:

The formula for this is a x b = c x d where a is SR, b is FR, c is QR and d is PR. This will give us the equation 9(16) = 8(5x + 8); 144 = 40x + 64; 80 = 40x; x = 2. Now, plug this into PR which will be 5(2)+8 = 18. This is your answer.

3 0
2 years ago
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