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Nezavi [6.7K]
3 years ago
9

I need some help with this problem, I am supposed to solve for x

Mathematics
1 answer:
harina [27]3 years ago
3 0
I havnt done that in a while but I think you do x+105=x+95 then you add your like terms which would turn into 10=2x then you divide 10 divided by 2 which is 5, SO YOUR ANSWER IS (I think) 5x
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Function P represents the perimeter, in inches, of a square with the side length x inches.
tatyana61 [14]

Answer:

   x =0,1,2,3,4,5,6

P(x) =0,4,8,12,16,20,24

Step-by-step explanation:

P(x)= 4x

4 x 1 = 4

4 x 2 = 8

4 x 3 =12

4 x 4 = 16

4 x 5 = 20

4 x 6 = 24

7 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Brandy has a new part-time job. On Monday, she worked 8 hours. On Wednesday, she worked three-fourths as long as she did on Mond
Setler79 [48]

Answer:

both of them are odd (because both of them are even, the reverse would be true)

Step-by-step explanation:

if she worked 8 on Monday, and on Wednesday worked for 3/4ths that amount of time she would've worked 6 hours. So an UNTRUE statement about this would be that they're both odd.

8 0
2 years ago
Consider the following expression and determine which statements are true.
Masja [62]

Answer:

m+5nx(9-p)-6-2r

The answer is b and d

Step-by-step explanation:

Hopefully this helped, if not HMU and I will gt you a better answer.

<em>-have a great day! :)</em>

<em />

5 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. log2 16 + log2 16 A. log2(28) B. 8 C. log 256 D. log2 2
eduard

Answer:

B. 8.

D.  log2 256.

Step-by-step explanation:

Generally:

loga b + loga b

= loga b^2.

Therefore log2 16 + log2 16

= log2 16^2

= log2 256.

From the above:

256 = 2^x   where x is the log.

Now 2^8 = 256   so the original log2 16 + log2 16 = 8.

3 0
2 years ago
Read 2 more answers
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