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dezoksy [38]
2 years ago
7

What is 27% as a fraction in the simplest

Mathematics
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer:

0.27

explanation

<u>27</u>

100

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• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re
MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
3 years ago
How many solutions does 5a-3=5a-3
olya-2409 [2.1K]

Answer:

0

Step-by-step explanation:

5a-3=5a-3

or, 5a-5a=-3+3

or, 0=0 answer

4 0
2 years ago
An 8 cm cube is cut into several small cubes of edge 2cm.how many cubes are formed ​
LiRa [457]
Its 8
not sure how to show the work but drew a pic and its 8
6 0
2 years ago
Write and solve a real-world problem that can be modeled by the equation 0.75x-18.50=0.65x Finding X the variable
Lubov Fominskaja [6]
I got x=185

0.75(185)-18.50=0.65(185)

120.25=120.25
6 0
3 years ago
Read 2 more answers
If a1=7 and an=an-1+5 than find the value of a5<br><br> ​<br> .
Katyanochek1 [597]

Answer:

a₅=27.

Step-by-step explanation:

1) according to the condition the given subsequence is arithmetic sequence. It means, the a₁=7 and d=5, then

2) a₅=a₁+4*d; => a₅=7+4*5=27.

4 0
2 years ago
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