Ask question

Ask question

All categories

3 years ago

5

jake said he has 8/100 of a dollar in his pocket Margie said that the decimal for 8/100 is 0.8 what error did she make. what is

the decimal form for 8/100?

2 answers:

expeople1 [14]3 years ago

5 0

Margie's mistake was where she placed the decimal point. the correct answer is 0.08.

lukranit [14]3 years ago

4 0

The 8 is in the tenths place it would look like 8/10 .8 its .08 for 8/100

You might be interested in

Solve 8[7-(6x-6)] 6x=0

aleksklad [387]

X=\frac{13}{6},\:x=0

8 0

4 years ago

Please help me out with equations in math!<br> Its a starr review!

Alexeev081 [22]

Answer:

F

Step-by-step explanation:

Multiply -3 by 6.5 and you'll get your answer :)

I hope I helped!

4 0

3 years ago

How do I find area of a circle if they only give me the diameter

disa [49]

Answer:

divide the diameter by 2

Step-by-step explanation:

the equation for the area of a circle is Pi times the radius squared. the radius is half the diameter, so if you need to find the area of the circle, just divide the diameter by 2 and you will have the length of the radius. then, jut plug it in to the equation.

7 0

3 years ago

Read 2 more answers

When simplified completely, the product of a monomial and a monomial is sometimesalwaysnever a monomial

Vaselesa [24]

Answer:

Always

Step-by-step explanation:

A mononomial's variable can only have exponents 0,1,2,3 etc so the product will also be a mononomial.

7 0

3 years ago

grandymaker [24]

Answer:

$\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1$

Step-by-step explanation:

An ellipse centered a point (h,k) has the following formula:

$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1$

The distance between foci is:

$2\cdot c = \sqrt{[8-(-8)]^{2}+(0-0)^{2}}$

$2\cdot c = 16$

$c = 8$

The center of the ellipse is:

$C(x,y) = (-8 + 8, 0 + 0)$

$C(x,y) = (0,0)$

The known vertex is on the horizontal axis of the ellipse. Then, the length of the semi-major axis is:

$a = \sqrt{(12-0)^{2}+(0-0)^{2}}$

$a= 12$

The length of the semi-minor axis is given by the following expression:

$c =\sqrt{a^{2}-b^{2}}$

$b = \sqrt{a^{2}-c^{2}}$

$b = \sqrt{12^{2}-8^{2}}$

$b \approx 8.944$

The equation of the ellipse is:

$\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1$

5 0

3 years ago