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dalvyx [7]
3 years ago
7

Rewrite for two solutions: (x – 3) = 11, –(x – 3) = 11  

Mathematics
1 answer:
ANEK [815]3 years ago
3 0

Answer:

x= 14, x=-14

Step-by-step explanation:

All you have to do is combine like-terms:

x-3=11

x=11+3, x=14

and,

-x-3=11

-x=11+3

-x=14 multiply by -1 so x can be positive,

x=-14

<em>Hope this helped and plz mark as brainliest!</em>

<em></em>

<em>Luna G.</em>

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24=7/8g I need help with this equation and explain how to do it please?
Gnesinka [82]
<span>      add</span><span> up the two equivalent fractions </span>
<span>Add the two equivalent fractions</span><span> which now have a common denominator</span>

<span>Combine the numerators together, put the sum or difference</span><span> over the common denominator then reduce to lowest terms if possible. tell me if this helped you.</span>
6 0
3 years ago
(6y + 3) minus (3y + 6) when y=7
never [62]

Answer:

y

Step-by-step explanation:

((((2•3y3) -  22y2) -  3y) -  —) -  2

                               y    

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  y  as the denominator :

                      6y3 - 4y2 - 3y     (6y3 - 4y2 - 3y) • y

    6y3 - 4y2 - 3y =  ——————————————  =  ————————————————————

                            1                     y          

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

5

:

Pulling out like terms

5.1     Pull out like factors :

  6y3 - 4y2 - 3y  =   y • (6y2 - 4y - 3)

Trying to factor by splitting the middle term

5.2     Factoring  6y2 - 4y - 3

The first term is,  6y2  its coefficient is  6 .

The middle term is,  -4y  its coefficient is  -4 .

The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   6 • -3 = -18

Step-2 : Find two factors of  -18  whose sum equals the coefficient of the middle term, which is   -4 .

     -18    +    1    =    -17

     -9    +    2    =    -7

     -6    +    3    =    -3

     -3    +    6    =    3

     -2    +    9    =    7

     -1    +    18    =    17

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Adding fractions that have a common denominator :

5.3       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

y • (6y2-4y-3) • y - (6)     6y4 - 4y3 - 3y2 - 6

————————————————————————  =  ———————————————————

           y                          y        

Equation at the end of step

5

:

 (6y4 - 4y3 - 3y2 - 6)    

 ————————————————————— -  2

           y              

STEP

6

:

Rewriting the whole as an Equivalent Fraction :

6.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  y  as the denominator :

        2     2 • y

   2 =  —  =  —————

        1       y  

Checking for a perfect cube :

6.2    6y4 - 4y3 - 3y2 - 6  is not a perfect cube

Trying to factor by pulling out :

6.3      Factoring:  6y4 - 4y3 - 3y2 - 6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -3y2 - 6

Group 2:  6y4 - 4y3

Pull out from each group separately :

Group 1:   (y2 + 2) • (-3)

Group 2:   (3y - 2) • (2y3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

6.4    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 6

Polynomial Roots Calculator is a set of methods aimed at finding values of  y  for which   F(y)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  y  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        1.00    

     -1       2        -0.50        -5.88    

     -1       3        -0.33        -6.11    

     -1       6        -0.17        -6.06    

     -2       1        -2.00        110.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(6y4-4y3-3y2-6) - (2 • y)      6y4 - 4y3 - 3y2 - 2y - 6

—————————————————————————  =  ————————————————————————

            y                            y            

Polynomial Roots Calculator :

6.6    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 2y - 6

    See theory in step 6.4

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -4.88    

     -1       3        -0.33        -5.44    

     -1       6        -0.17        -5.73    

     -2       1        -2.00        114.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Final result :

 6y4 - 4y3 - 3y2 - 2y - 6

 ————————————————————————

            y            

4 0
2 years ago
Read 2 more answers
A first number plus twice a second number is 14. Twice the first number plus the second totals 10. Find the numbers.
Nookie1986 [14]

Answer:

first number(x) = 2 second number(y)= 6

Step-by-step explanation:

This is an example of a simultaneous equation.

First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".

x + 2y = 14  (equation 1)

2x + y = 10  (equation 2)

This is solved using the elimination method.

We need to make one of the coefficients the same - in this case we can make y the same. In order to do this we need to multiply equation 2 by 2, so that y becomes 2y.

2x + y = 10 MULTIPLY BY 2

4x + 2y = 20 (this is now our new equation 2 with the same y coefficient)

Now subtract equation 1 from equation 2.

4x - x + 2y - 2y = 20 - 14  (2y cancels out here)

3x = 6

x = 2

Now we substitute our x value into equation 1 to find the value of y.

2 + 2y = 14

2y = 12

y = 6

Hope this has answered your question.

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3 years ago
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Step-by-step explanation:

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