Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer:
x-intercept = 12, y-intercept = 4
Step-by-step explanation:
To find the x and y intercept, substitute 0 in for both values.
<u>Substitute 0 into x:</u>
2(0) + 6y = 24
6y = 24
<u>Divide each side by 6:</u>
y = 4
<u>Substitute 0 into y:</u>
2x + 6(0) = 24
2x = 24
<u>Divide each side by 2:</u>
x = 12
Answer:
11p + 2m
Step-by-step explanation:
10m - 8m = 2m
12p - p = 11p!
So Overall it would be
= 11p + 2m
I believe that Mr.Scruggs got $225 for his birthday, if my math is correct of course. :) I hope this helps! Have a great day!
