You have two cards with a sum of (-12) In your hand.what two cards could you have?Give 2 examples

1 answer:

6 0

-6 and -6 because -6 + -6 = -12 , you could also have -8 and -4 because -8 + -4 = -12, or you could also have -10 and -2 because -10 + -2 = -12

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Answer:

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Step-by-step explanation:

We are given that Let z denote a random variable that has a standard normal distribution.

Let Z = a random variable

So, Z ~ Standard Normal(0, 1)

As we know that the standard normal distribution has a mean of 0 and variance equal to 1.

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)