The smallest of the even integers is 8.
It is a well-known fact that the sum of the first n odd numbers is n^2. This makes the sum of the first 8 odd numbers equal to 64.
Let n be equal to the smallest of the 5 even integers. Then (n+2) is the next highest, (n+4) even higher, and so on.
This sets up the equation n+(n+2)+(n+4)+(n+6)+(n+8)+4=64
Now we solve:
5n+24 = 64
5n = 40
n = 8
The smallest of the even integers is 8.
Learn more about integers here: brainly.com/question/14453211
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Answer:
140
Step-by-step explanation:
140 is the first multiple that all 3 numbers share.
Answer:
It seems that your options aren't correct as the right answer is -5.3333... (recurring)
Step-by-step explanation:
1) 2x + 4 = 20 + 5x (subtract by the smallest unknown)
-2x -2x
2) 4 = 20 + 3x
-20 -20 (now subtract each side by 20 as we want to leave the unknown on one side and another number on the other side.
3) -16 = 3x (Divide each side by 3)
÷3 = ÷3
4) -5.33333... = x
<h3>Now we have found x but if you're unsure you can substitute to see if your answer is correct.</h3><h3>2 x -5.3333 + 4 = -6.6666</h3><h3>20 + 5 x -5.3333= -6.6665</h3><h3>Our answer is correct! (When answers are rounded, it is equal to the same thing).</h3>