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nalin [4]
2 years ago
15

Julia's car used 1/100 of a gallon to travel 0.25 miles. How many miles can the car go on one gallon of gas? On the double numbe

r line below, fill in the given values, then use multiplication to find the missing value. Enter your answers as fractions, whole numbers, or decimals. miles 0 gallons Enter your final answer as a whole number or decimal.​
Mathematics
1 answer:
Margaret [11]2 years ago
5 0

Answer:

25 miles

Step-by-step explanation:

well
1/100 = 0.25
10/100 = 2.5 (Because 0.25 x 10)
100/100 = 25 (Because 0.25x100)

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80 points, need ASAP
Tresset [83]

9x^2 -c =d

add c to each side

9x^2 = c+d

divide by 9

x^2=(c+d)/9

take the square root on each side

x = +- sqrt ((c+d)/9)

simplify

x = +- 1/3 sqrt (c+d)

Answer: 1/3 sqrt (c+d), - 1/3 sqrt (c+d)

7 0
3 years ago
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2(5x + 4) = 8<br> 10x + 8 = 8<br> -[?] - [ ]
GarryVolchara [31]

Answer:

-5-2

Step-by-step explanation:

10*+8=8

-5-2

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4 0
2 years ago
10 to 15 simplified
pashok25 [27]
2/3
Divide the numerator and denominator by their gcd which is 5
4 0
3 years ago
Read 2 more answers
Which expression is equivalent to 2x-2(20-3x)+12
Darina [25.2K]

Answer:

-7x-48

Step-by-step explanation:

2x-3(20-3x)+12

2x-60-9x+12     (distribute)

-7x-48

hope this helps

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6 0
3 years ago
Jeffrey went to the movies with his friends. The tickets cost $8.50 each for students and they spent $15.00 altogether at the co
LenaWriter [7]

Answer:

4 people

Step-by-step explanation:

Let's first write an equation.

We want to find the number of tickets t

The total was $49 so our equation will equal $49 and they spent $15 in snacks so on the other side of the eqaution we have to add $15, on the same side as the snacks we need to add in the cost of tickets, which is $8.50 multiplies by t, or the total number of tickets.

$49 = $8.50t + $15

Solve for t, first subtract $15 from both sides.

$49 - $15 = $8.50t

$34 = $8.50t   Divide both sides by $8.50

$34/$8.50 =  $8.50t/$8.50  

$34/$8.50 = t

4 = t

4 tickets meaning 4 people went.

7 0
3 years ago
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